Answer:
y = 3/4x - 5
Step-by-step explanation:
An equation of a line can be written in slope-intercept form:
y = mx + b
where m is the slope and b is the y-intercept.
Let's plug in what we know.
The slope is 3/4.
y = 3/4x + b
To find b, we want to plug in a value that we know is on this line: in this case, I will use the point (4, -2). Plug in the x and y values into the x and y of the standard equation.
-2 = 3/4(4) + b
To find b, multiply the slope and the input of x(4)
-2 = 3 + b
Now, subtract 3 from both sides to isolate b.
-5 = b
Plug this into your standard equation.
y = 3/4x - 5
This is your equation. It has a slope of 3/4, and passes through (4, -2)
Hope this helps!
From the question, we know that we will be looking at <3, <4, and angles TKL and TLK. That being said, since <3 is congruent to <4, that means that angles TKL and TLK, which are each supplementary to either angle 3 or 4, are congruent because, since angles 3 and 4 are congruent, they are congruent because the supplements of congruent angles are congruent.
Answer:
19,27 cm^2
Step-by-step explanation:
area of triangle = (6 x 3)/ 2 = 9 cm^2
circle area : 3^2 x 3,14 = 28,27 cm^2
area of shaped region = 28,27 - 9 = 19,27 cm^2
Answer:
I and IV
Step-by-step explanation:
cosine is positive/greater than 0 in quadrants I and IV. Its just a rule of the unit circle.
Can remember by All Star Trig Class
meaning all the trig funtions are positive in quadrant I
sin is positive in II
tan is positive in III
and cos is positive in IV
Answer:
Step-by-step explanation:
Given
Required
This is calculated as:
