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seropon [69]
3 years ago
14

Find the range and the first and third quartiles for the data set. 45,42,86,13,74,47,46

Mathematics
1 answer:
Evgen [1.6K]3 years ago
3 0

To find the range subtract from the biggest to the lowest, so it would be 86 - 13 which equals to 73.

Your lower or first quartile would be 42 and your upper or third quartile would be 74.

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Step-by-step explanation:

Using PEMDAS;

Step 1: Distribute the "3" in the part of the equation "3(x-2)"

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8 0
4 years ago
I need help with number 4, thank you
LiRa [457]

Answer:

<h2><em><u>126</u></em></h2>

Step-by-step explanation:

<em>In</em><em> </em><em>number</em><em> </em><em>4</em><em> </em><em>the</em><em> </em><em>given</em><em> </em><em>figure</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>parallelogram</em><em>, </em>

<em><u>So</u></em><em><u>,</u></em>

Base of the parallelogram = 14

Height of the parallelogram = 9

<em><u>Therefore</u></em><em><u>, </u></em>

Area of the parallelogram = <em><u>Base</u></em><em><u> </u></em><em><u>×</u></em><em><u> </u></em><em><u>Height</u></em><em><u> </u></em>

= 14 × 9

= 126

<em><u>Hence</u></em><em><u>,</u></em><em><u> </u></em><em><u>area</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>figure</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>question</u></em><em><u> </u></em><em><u>no</u></em><em><u>.</u></em><em><u> </u></em><em><u>4</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>12</u></em><em><u>6</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>

8 0
3 years ago
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