Answer:
The expression that comes after solving the two linear equation is independent of variables So , The system of equations has <u>no solutions </u>
Step-by-step explanation:
Given two linear equations as :
2 y - 4 x = 6 .......1
y - 2 x = 7
Or, y = 2 x + 7 .......2
Now, Solving these two equations
Put the value of y from eq 2 into eq1
So, 2 y - 4 x = 6
∴ 2 × (2 x + 7) - 4 x = 6
Or, 4 x + 14 - 4 x = 6
or, (4 x - 4 x) = 6 - 14
i.e 0 = - 8
∵ The expression that comes after solving the two linear equation is independent of variables So , The system of equations has no solutions Answer
The vertical asymptotes of a function secant are determined by the points that are not in domain.
Thank you.
52.20÷3= 17.40×5=87. The meal cost £87
I can’t really explain but this is my working step by step, hope u can understand and see if it helps you :)
May be there is an operator missing in the first function, h(x). I will solve this in two ways, 1) as if the h(x) = 5x and 2) as if h(x) = 5 + x
1) If h(x) = 5x and k(x) = 1/x
Then (k o h) (x) = k ( h(x) ) = k(5x) = 1/(5x)
2) If h(x) = 5 + x and k (x) = 1/x
Then (k o h)(x) =k ( h(x) ) = k (5+x) = 1 / [5 + x]
