Question

At 1:00 p.m. one bus leaves Anandpur to Shivnagar which is 255 km apart and travels at an average speed of 45 km/hour. At the same time another bus leaves shivnagar to Anandpur at an average speed of 40 km/hour. Find when and where will they cross each other

Answer 1

Answer:

The buses will cross after 3 hours at a distance of  135 km away from Anandpur

Step-by-step explanation:

Distance between Anandpur and Shivnagar  255 km

Bus 1 leave at 1:00 p.m. Its speed is  45 km

Bus 2  leaves at the same time with a speed of 40 km/hour.

Now the Let the time  at which ther across each other be x . then

Distance covered  Bus 1 at t time +distance covered by Bus 2 at t time =  distance between anandpur and shivnagar-----------------(1)

Distance covered  Bus 1 at t time

Distance = speed  x  time

Distance  = 45 t

Distance covered by Bus 2 at t time

Distance = speed  x  time

Distance  = 40 t

Now, Substituting then values in (1)

45t +40t = 255

85t = 255

t =$\frac{255}{85}$

t = 3 hour

anandpur speed to reach at 4:00PM

distance =time×speed

d=3×45

135 km away from anandpur