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SCORPION-xisa [38]
3 years ago
9

What times what is 30

Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
5 0
It could be (1*30), (2*15), (3*10), (5*6)
You might be interested in
Will mark brainlest
aleksklad [387]

Divide y by x:

150/10 = 15

135/9 = 15

30 /2 = 15

They all equal 15


This means the constant of proportionality would be y = 15x


The answer is C.

7 0
3 years ago
Read 2 more answers
Camila sets up a passcode on her tablet, which allows only nine-digit codes. A spy sneaks a look at Camila's tablet and sees her
laila [671]

Answer:

\frac{1}{10^9} probability the spy is able to unlock the tablet on his first try.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Desired outcomes:

1 correct password, so D = 1

Total outcomes:

Nine-digit codes.

For each digit, there are 10 possible outcomes. So

T = 10^9

What is the probability the spy is able to unlock the tablet on his first try?

p = \frac{D}{T} = \frac{1}{10^9}

\frac{1}{10^9} probability the spy is able to unlock the tablet on his first try.

7 0
3 years ago
For what value of c does the following system have no solution?<br><br> 1/2x+1/5y=2<br> 5x+2y=c
Minchanka [31]

Answer:

Step-by-step explanation:

\frac{1}{2}x+\frac{1}{5}y = 2 \mid 5x + 2y = c

First let's multiply the 1st equation by 10.

5x + 2y = 20 \mid 5x + 2y = c

So, we can see that the equations have the same coefficients and that implies  they are equal.

So the equation has no solutions for. c \in R \setminus{20}

3 0
2 years ago
Read 2 more answers
ABCD is a trapezoid.<br> What is the area of trapezoid?
lana [24]
Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
  Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
  Area = (1/2)(AB + AB/4)·h = (5/8)AB·h

The given dimensions let us determine the area of ∆BCE to be
  Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²

The total area of the trapezoid is also the sum of the areas ...
  Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
  Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
  Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h

Putting all of the above into the equation for the total area of the trapezoid, we have
  Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
  (5/8 -1/6 -1/12)AB·h = 30 cm²
  AB·h = (30 cm²)/(3/8) = 80 cm²

Then the area of the trapezoid is
  Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²
6 0
3 years ago
The 45°- 45° - 90° Triangle Theorem states that the length of the hypotenuse is ________ times the length of one leg.
Airida [17]
 <span>This is an isosceles triangle. If each side is 1, we can find the hypotenuse using the Pythagorean theorem. 

a^2 + b^2 = c^2 
1^2 + 1^2 = c^2 
1 + 1 = c^2 
2 = c^2 
root 2 = c 

Thus, the answer is root 2.

Hope this helps :)</span>
3 0
3 years ago
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