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Eduardwww [97]
3 years ago
8

You can write as many constructors for a class as you want, as long as they all have different ____ lists.

Computers and Technology
1 answer:
arlik [135]3 years ago
5 0
<span>You can write as many constructors for a class as you want, as long as they all have different argument lists.</span>
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While engineers work to create computers that can understand us emotionally, ________ are also evolving toward a more human appe
aleksandrvk [35]
While engineers work to create computers that can understand us emotionally, ________ are also evolving toward a more human appearance.

affecting computing techniques
8 0
3 years ago
In 1972, earlier designers built the
Sonbull [250]

The exercise is about filling in the gaps and is related to the History of the ARPANET.

<h3>What is the History of the ARPANET?</h3>

From the text:

In 1972, earlier designers built the <u>ARPANET </u>connecting major universities. They broke communication into smaller chunks, or <u>packets </u>and sent them on a first-come, first-serve basis. The limit to the number of bytes of data that can be moved is called line capacity, or <u>bandwidth</u>.

When a network is met its capacity the user experiences <u>unwanted pauses</u>. When the network is "slowing down", what is happening is users are waiting for their packet to leave the <u>queue</u>.

To make the queues smaller, developers created <u>mixed </u>packets to move <u>simultaneously</u>.

Learn more about the ARPANET at:
brainly.com/question/16433876

7 0
3 years ago
Chegg Suppose the heap is a full tree, size 2^n-1. what is the minimum number of steps to change a min heap to a max heap. Show
adoni [48]

Answer:

Explanation:

We start from the bottom-most and rightmost internal node of min Heap and then heapify all internal modes in the bottom-up way to build the Max heap.

To build a heap, the following algorithm is implemented for any input array.

BUILD-HEAP(A)

   heapsize := size(A)

   for i := floor(heapsize/2) downto 1

       do HEAPIFY(A, i)

   end for

Convert the given array of elements into an almost complete binary tree.

Ensure that the tree is a max heap.

Check that every non-leaf node contains a greater or equal value element than its child nodes.

If there exists any node that does not satisfy the ordering property of max heap, swap the elements.

Start checking from a non-leaf node with the highest index (bottom to top and right to left).

4 0
3 years ago
The coordinates for the section element need not be defined as long as its position is set to
scoray [572]
<h2><u>Answer:</u></h2>

relative.

<h2><u>Explanation:</u></h2>

The coordinates for the section element need not be defined as long as its position is set to relative.

If the position is set as relative, then it will have no effect on the positioning attributes, it will consider as static position. If positioning is mentioned explicitly like top: 20px; then it will position 10 pixels down from where it is located. An ability for positional shifts is extremely helpful.

Two things happen when an element is set as relative, one is it introduces the ability to use z-index on that element, second is it limits the scope of absolutely positioned child elements.  

5 0
2 years ago
You should see the following code in your programming
Karo-lina-s [1.5K]

Answer:

import simplegui

import random

def draw_handler(canvas):

for x in range(1000):

colorList = ["Yellow", "Red", "Purple", "White", "Green", "Blue", "Pink", "Orange"]

c = random.choice(colorList)

x = random.randint(1,600)

y = random.randint(1,600)

canvas.draw_point([x, y], c)

frame = simplegui.create_frame('Testing', 600, 600)

frame.set_canvas_background("Black")

frame.set_draw_handler(draw_handler)

frame.start()

Explanation:

I used a for loop, setting my range to 1000 which is how you create exactly 1000 points. Next, I defined my color array, my x randint value, and my y randint value. I set both the x and y randint values to 1 - 600 since the frame is 600x600. The rest is pretty self explanatory.

4 0
3 years ago
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