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Temka [501]
3 years ago
13

Using the rhombus below, what is m<CDE

Mathematics
1 answer:
sveticcg [70]3 years ago
7 0
I think the angle would have to be 115, I am pretty sure, If you see the angle by 65 then the other one would have to be 115 to equal 180

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The rectangle shown has length AC = 32, width
Elena-2011 [213]

Answer:

A. 320

Step-by-step explanation:

See attachment for the figure

in order to determine Area of quadrilateral ABDF, we'll use the formula i.e

Area of quadrilateral ABDF = Area of AECD - Area of ΔBCD - Area of ΔDEF ->eq(1)

whereas, area of AECD = (AC × AE)

Area of ΔBCD = 1/2 (BC x CD)

Area of ΔDEF =1/2 ( EF x ED)

Substituting in eq(1)

eq(1)=>

Area of quadrilateral ABDF =  (AC × AE)  - 1/2 (BC x CD)- 1/2 ( EF x ED)

                  =(32 x 20) - 1/2(16 x 20) - 1/2(10 x 32)

                  = 640 - 160 - 160

                  = 640 - 320

                 = 320 square unit

Therefore, the area of quadrilateral ABDF is 320 square unit

8 0
3 years ago
What is the measure of the angle marked to the nearest 10th? (giving brainliest and thanks to all!)
Svet_ta [14]
31.9 i believe, hopefully this worked
3 0
3 years ago
Reflection of -2,4 1,2 -2,1 across x axis
Sveta_85 [38]

Answer:

2,4   -1,2   2,1

Step-by-step explanation:

4 0
3 years ago
HELP ME OUT PLEASE ASAP
White raven [17]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
Find x.<br><br><br><br> \/3<br> 1.5<br> 3 \/3<br> 2
serg [7]

x = \sqrt{3}

Step-by-step explanation:

Given:

\sin(ABC) =  \frac{AC}{AB}

=  >  \sin(60) =  \frac{3}{AB}

=  >AB= 2 \sqrt{3}

Now by Pythagoras theorem,

AC^{2} + BC^{2} = AB^{2}

Substituting values,

{3}^{2} +  {x}^{2} = (2 \sqrt{3})^{2}

=  >  {x} =  \sqrt{3}

Hence, value of x is \sqrt{3}

3 0
2 years ago
Read 2 more answers
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