Answer:
Lesser = -
- 7 = -10.317
Greater = + - 7 = -3.683
Step-by-step explanation:
I am assuming you are asking for the lesser x solution and greater x solution.
(x + 7)^2 – 11 = 0
(x + 7)^2 = 11
x+7 = ±
x = ± - 7
Lesser = - - 7 = -10.317
Greater = + - 7 = -3.683
Answer:
Step-by-step explanation:
Neither are a function because they do not pass the vertical line test.
Answer: Both A, and C
Step-by-step explanation:
The answer to the first system of equations (2x+2y=16) would be
x=3 and y=5 ( 3x-y=4 )
Which means we have to find out which of the other equations has an x value of 3, and a y value of 5.
If A is 2x+2y=16, then x=3 and y=5
6x-2y=8
If B is x+y=16, then x=5 and y=11
3x-y=4
If C is 2x+2y=16, then x=3 and y=5
6x-2y=8
If D is 6x+6y=48 , then x=-2 and y=10
6x+2y=8
Both A and C are equal to the first system of equations, which means they are both correct answers.
Answer:
Step-by-step explanation:
(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2
Adding and substracting 2x^2y^2
We get
(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2 +2x^2y^2-2x^2y^2
And we know a^2-2ab+b^2=(a-b)^2
So we identify (x^2)^2 as a^2 ,(y^2)^2 as b^2 and -2x^2y^2 as - 2ab. So we can rewrite (x^2+y^2)^2=(x^2 - y^2)^2 + 2x^2y^2 + 2x^2y^2= (x^2 - y^2)^2+4x^2y^2= (x^2 - y^2)^2+2^2x^2y^2
Moreever we know (a·b·c)^2=a^2·b^2·c^2 than means 2^2x^2y^2=(2x·y)^2
And (x^2+y^2)^2=(x^2 - y^2)^2 + (2x·y)^2
Answer:
x=2-y/2
y=12/7-6x/7
Step-by-step explanation:
