Answer:
W/5-6
Step-by-step explanation:
W/5-6
W/1
Given that the subway stations are 930 m apart, the train have to be accerelated for half the distance and then decerelated for the rest of the distance.
Recall that the distance travelled by an object with an initial velocity, u, for a period of time, t, at an accereration, a, is given by

But, we assume that the train accelerates from rest, thus

The maximum speed is attained at half the center of the distance between subway stations (i.e. at distance = 465 m).
Thus, maximum speed = distance / time = 465 / 23.12 = 20.11 m/s.
Answer:
21.835 kilograms
Step-by-step explanation:
(4,367x5)/1000
I dont quite undeerstand but the gcf for both are..., if that helps is 4 because
30:2*2*2*2*2
22:2*2 5
Hmmm wait let me try to do it