Hey here is the answer to ur question...
5x^2-2xy+y^2
=>5*(-2)^2-2*-2*3+(3)^2
=>5*4+12+9
=>20+12+9
=>41
Hope this helps u....!!!
The first five terms of the recursively defined sequence are 6, 12, 48, 768, 196608
For given question,
We have been given the recursive formula of a sequence.

Also, the first term of the sequence is,
a1 = 6
Substitute k = 1 in given recursive formula.
⇒ 
⇒ a2 = 1/3 (6)²
⇒ a2 = (1/3) × 36
⇒ a2 = 12
Substitute k = 2 in given recursive formula.
⇒ 
⇒ a3 = (1/3) × (12)²
⇒ a3 = (1/3) × 144
⇒ a3 = 48
Substitute k = 3 in given recursive formula.
⇒ 
⇒ a4 = (1/3) × (48)²
⇒ a4 = (1/3) × 2304
⇒ a4 = 768
Substitute k = 4 in given recursive formula.
⇒ 
⇒ a5 = (1/3) × (768)²
⇒ a5 = (1/3) × 589824
⇒ a5 = 196608
Therefore, the first five terms of the recursively defined sequence are 6, 12, 48, 768, 196608
Learn more about the recursive formula of sequence here:
brainly.com/question/14457800
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Answer:
No solution
Step-by-step explanation:
Given two equations are 2x+4y= -8 and 4x+8y= 5
These two lines are parallel They don't have a solution because they do not meet .
Multiply the first equation by 2 we get 4x+8y = -16
the other equation is 4x+8y= 5 clearly these two are parallel .
To prove by elimination method we have subtract those two equations we get 21≠0 which is not possible.
Therefore there is no solution to the given set of equation.