Answer:
9/16
Explanation:
Let broad, straight wings be represented by the allele W. Homozygous condition will be WW or ww while heterozygous condition will be Ww
Let pale-colored body with dark transverse stripes is represented by C. Homozygous condition will be CC or cc while heterozygous condition will be Cc.
Heterozygous condition for both trait will be WwCc. Hence a mating between two flies that are heterozygous for both trait will be;
WwCc x WwCc
This will yield offspring in the following phenotypic ratio;
Broad, straight wings with pale-colored body/dark transverse stripes - 9/16
Broad, straight wings with ebony body colour - 3/16
Nubby, vestigial wings with pale-colored body/dark transverse stripes - 3/16
Nubby, vestigial wings with ebony body colour - 1/16.
See the attached image for the Punnet square result of the cross.
The proportion is 9/16
Disadvantage:
1. Cause health problems for animals eating the product.
2. Some GM foods may contain allergens and toxins.
3. Gene transfer may occur between organisms.
Answer:
C
Explanation:
The Calvin cycle occurs in three major phases:
1) Carbon fixation; which involves the reaction of CO2 with a phosphorylated Co2 acceptor called Ribulosebiphosphate(RuBp) as catalysed by Rubisco enzyme. Due to the instability of the formed six-carbon compound, it breaks into two molecules of 3-phosphoglycerate (PGA)
2) Reduction; The PGA is phosphorylated by ATP to form 1,3-biphosphoglycerate, which is then reduced by NADPH to form glyceraldehyde-3-phosphate (G3P).
3) Regeneration; The final step, which is very important for the continuity of Calvin cycle is the regeneration of the CO2 acceptor (RUBP). The molecules of G3P are rearranged into molecules of Ribulosephosphate(RuP) by series of complex reactions, which is then phosphorylated by ATP to form RUBP, ready to accept CO2 for the cycle to continue