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DENIUS [597]
4 years ago
12

Who invented the square root of negative one?

Mathematics
1 answer:
telo118 [61]4 years ago
6 0
I believe it would be jack Dorsey and jim Mckelvey since they were the ones who made the perfect square
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A little boy is placing 20 oh his marbles in a row. If 12 are red and 8 are blue and he decides not to place 2 blue marbles next
aleksandr82 [10.1K]

Answer:

Consider lining up all the blue marbles and placing one red marble in between them. Let that arrangement be fixed. The remaining red marbles will be 5 red marbles. Note that the arrangement will be:

x BR x BR x BR x BR x BR x BR x BR x B x

Note that this is the same even if our arrangement is

x B x RB x  RB x RB x RB x RB x RB x RB x

Note that there are 9 spots, denoted by x, where we can put the 5 remaining red marbles. To find the number of ways of putting the remaining 5 red marbles to x, it is similar in finding the number of non-negative solution for the equation

a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7 + a_8 + a_9 = 5

which is given by

(^{5+9-1}_{9-1}) = 1287

Hence, there are 1287 ways of arranging 8 blue marbles and 12 red marbles without placing 2 blue marbles next to each other.

6 0
4 years ago
I Can Multiply The Number Of_______In A Polygon By________To Find The Sum Of Its Interior Angles
stealth61 [152]
Multiply the sides by 180  degrees!!!!!!
3 0
4 years ago
A 0.02 N push accelerates a table-tennis ball along a table at 8 m/s2 north. What is the mass of the ball?
Rashid [163]
  • Force=0.02N=F
  • Acceleration=a=8m/s^2
  • Mass=m

According to Newton's second law

\\ \sf\longmapsto F=ma

\\ \sf\longmapsto m=\dfrac{F}{a}

\\ \sf\longmapsto m=\dfrac{0.02}{8}

\\ \sf\longmapsto m=0.0025kg

\\ \sf\longmapsto m=2.5g

5 0
3 years ago
A certain pizza box holds a 14-inch diameter pizza. If the box is 2 inches high, what is its surface area?
MakcuM [25]

Answer:

36

Step-by-step explanation:

7 0
3 years ago
if f(x) = ax^6 + bx^4 + cx^3 where a,b, and c are integers, how many distinct rational zeros could f(x) have
natita [175]

You can rewrite your function as

f(x) = x^3(ax^3+bx+c)

This implies that

f(x)=0 \iff x^3=0\quad\lor\quad ax^3+bx+c=0

Now, we have x^3=0\iff x=0, so it counts as a solution.

On the other hand, depending on the coefficient a, b and c, the cubic equation

ax^2+bx+c=0

can have either one or three solutions.

So, we have the solution x=0, and then one or three solutions coming from the cubic part. The equation as a whole thus have either two or four solutions, depending on the coefficients.

8 0
4 years ago
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