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Lapatulllka [165]
2 years ago
15

A 0.02 N push accelerates a table-tennis ball along a table at 8 m/s2 north. What is the mass of the ball?

Mathematics
1 answer:
Rashid [163]2 years ago
5 0
  • Force=0.02N=F
  • Acceleration=a=8m/s^2
  • Mass=m

According to Newton's second law

\\ \sf\longmapsto F=ma

\\ \sf\longmapsto m=\dfrac{F}{a}

\\ \sf\longmapsto m=\dfrac{0.02}{8}

\\ \sf\longmapsto m=0.0025kg

\\ \sf\longmapsto m=2.5g

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Help really fast round 93.0129 to the nearest thousandth
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<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B125%20%7D%20-%20%5Csqrt%7B180%7D%20%2B%20%5Csqrt%7B45%7D%20" id="TexFormula1" tit
Kobotan [32]

Answer:

2\sqrt{5}

Step-by-step explanation:

Using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

Simplifying the radicals

\sqrt{125} = \sqrt{25(5)} = \sqrt{25} × \sqrt{5} = 5\sqrt{5}

\sqrt{180} = \sqrt{36(5)} = \sqrt{36} × \sqrt{5} = 6\sqrt{5}

\sqrt{45} = \sqrt{9(5)} = \sqrt{9} × \sqrt{5} = 3\sqrt{5}

Thus

\sqrt{125} - \sqrt{180} +\sqrt{45}

= 5\sqrt{5} - 6\sqrt{5} + 3\sqrt{5}

= 2\sqrt{5}

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