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3 years ago

Whats the value of Sin 60° + cos 60° ???

Mathematics

2 answers:

AlexFokin [52]3 years ago

3 0

Answer:

1.366

Step-by-step explanation:

sin60 = 0.866

cos60 = 0.5

0.866 + 0.5 = 1.366

bixtya [17]3 years ago

3 0

Answer:

1.36602540378

Step-by-step explanation:

sin 60 degrees = 0.86602540378

cos 60 degrees = 0.5

0.86602540378 + 0.5 = 1.36602540378

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Which ordered pair is a solution to the system of linear equations 1/2x-3/4y=11/60 and 2/5x+1/6y=3/10

natka813 [3]

ANSWER

$( \frac{2}{3} , \frac{1}{5} )$

EXPLANATION

The first equation is

$\frac{1}{2} x - \frac{3}{4} y = \frac{11}{60} ...(1)$

The second equation is

$\frac{2}{5} x + \frac{1}{6} y = \frac{3}{10} ...(2)$

We want to eliminate y, so we multiply the first equation by

$\frac{4}{5}$

$\frac{4}{5} \times \frac{1}{2} x - \frac{4}{5} \times \frac{3}{4} y = \frac{11}{60} \times \frac{4}{5}$

$\frac{2}{5} x - \frac{3}{5} y = \frac{11}{75} ...(3)$

We now subtract equation (3) from (2)

$(\frac{2}{3} x - \frac{2}{3} x )+ ( \frac{1}{6} y - - \frac{3}{5}y ) =( \frac{3}{10} - \frac{11}{75} )$

$\frac{1}{6} y + \frac{3}{5}y =\frac{3}{10} - \frac{11}{75}$

$\frac{23}{30}y = \frac{23}{150}$

Multiply both sides by

$\frac{30}{23}$

$\implies \: \frac{30}{23} \times \frac{23}{30}y= \frac{23}{150} \times \frac{30}{23}$

$\implies \: y = \frac{1}{5}$

Substitute into the first equation to solve for x .

$\frac{1}{2} x - \frac{3}{4} \times \frac{1}{5} = \frac{11}{60}$

Multiply to obtain

$\frac{1}{2} x - \frac{3}{20} = \frac{11}{60}$

$\frac{1}{2} x = \frac{11}{60} + \frac{3}{20}$

$\frac{1}{2} x = \frac{1}{3}$

Multiply both sides by 2.

$2 \times \frac{1}{2} x =2 \times \frac{1}{3}$

$x = \frac{2}{3}$

The solution is

$( \frac{2}{3} , \frac{1}{5} )$

5 0

3 years ago

Read 2 more answers

Which expression is equivalent to 6+4.5(32f-14f)

vichka [17]

Answer:

$6 + 4.5(32f - 14f) = 6 + 81f$

Step-by-step explanation:

Let us apply the distributive property to find an equivalent expression for:

$6 + 4.5(32f - 14f)$

For all real numbers a, b, and c, the distributive property says that:

$a(b + c) = ab + ac$

We apply this property to get:

$6 + 4.5(32f - 14f) = 6 + 4.5 \times 32f + 4.5 \times - 14f$

$6 + 4.5(32f - 14f) = 6 + 144f - 63f$

We simplify the RHS to get:

$6 + 4.5(32f - 14f) = 6 + 81f$

8 0

4 years ago

PLEASE HELP ILL GIVE U BRAINLIEST PLSS!!!!!! I ONLY HAVE 1 HOUR PLSSSSSSS!!!!

natta225 [31]

Answer:

Upper left: the answer is 2, becuase 2 times 5x = 10x

Upper right: the answer is 4y, because 6 times 4y = 24y

Lower left: the answer is 3, because 3 times 3a+2b = 9a+6b

Lower right: the answer is 3a+2b, because 4 times 3a+2b =12b+8b

Let me know if this helps!

6 0

3 years ago

What is the product of (5 Superscript negative 1 Baseline) (5 Superscript negative 3 Baseline)? StartFraction 1 Over 625 EndFrac

Oksana_A [137]

Answer:

Step-by-step explanation:

Given the indicinal equation

5^-1/5^-3

According to one of the law of indices, if a, b, m and n are integers then;

a^m/a^n = a^(m-n)

When the base are equal, the powers will be subtracted.

Applying this formula to the given expression

5^-1/5^-3

= 5^{-1-(-3)}

= 5^(-1+3)

= 5^2

= 25

Therefore the answer is 25

5 0

4 years ago

Read 2 more answers

Two cars leave Phoenix and travel along roads 90 degrees apart. If Car 1 leaves 30 minutes earlier than Car 2 and averages 42 mp

romanna [79]

Answer:

C. 210 miles

Step-by-step explanation:

We have been given that two cars leave Phoenix and travel along roads 90 degrees apart. Car 1 leaves 30 minutes earlier than Car 2 and averages 42 mph.

We will use distance formula and Pythagoras theorem to solve our given problem.

$\text{Distance}=\text{Speed}\times \text{Time}$

$\text{Distance covered by Car 1 in 3.5 hours}=\frac{42\text{ Miles}}{\text{Hour}}\times \text{3.5 hour}$

$\text{Distance covered by Car 1 in 3.5 hours}=147\text{ Miles}$ .

Since car 1 leaves 30 minutes before car 2, so car 2 will travel for only 3 hours when car 1 will travel for 3.5 hours.

$\text{Distance covered by Car 2 in 3 hours}=\frac{50\text{ Miles}}{\text{Hour}}\times \text{3 hour}$

$\text{Distance covered by Car 2 in 3 hours}=150\text{ Miles}$

Since both car travel along roads 90 degree apart, therefore, the distance between both cars after Car 1 has traveled 3.5 hours would be hypotenuse with legs 147 and 150.

$\text{Distance between both cars}=\sqrt{147^2+150^2}$

$\text{Distance between both cars}=\sqrt{21609+22500}$

$\text{Distance between both cars}=\sqrt{44109}$

$\text{Distance between both cars}=210.021427\approx 210$

Therefore, the both cars will be 210 miles apart and option C is the correct choice.

3 0

3 years ago