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oksano4ka [1.4K]
3 years ago
15

Question 3: 12 points

Mathematics
1 answer:
Dvinal [7]3 years ago
8 0

Answer:

9x^{5}y^{5} yards.

Step-by-step explanation:

Given that the area of a rectangle (A) is 45x^{8}y^{9} square yards.

If the length of the rectangle (L) is given to be 5x^{3}y^{4} yards, then we have to find the width (W) of the rectangle in yards.

Now, A = L × W

⇒ W = \frac{A}{L} = \frac{45x^{8}y^{9}}{5x^{3}y^{4}} = (\frac{45}{5})\times (\frac{x^{8}}{x^{3}}) \times (\frac{y^{9}}{y^{4}}) = 9x^{8 - 3}y^{9 - 4} = 9x^{5}y^{5} yards. (Answer)

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A delivery truck is transporting boxes of two sizes: large and small. The large boxes weigh 50 pounds each, and the small boxes
skad [1K]
So this is how we are going to solve for the given problem above.
Given that x = number of large boxes
and 120-x = number of small boxes.
So here is the solution:
50x + (120-x)20 = 4050
50x + 2400 - 20x = 4050
30x + 2400 = 4050
30x = 4050 - 2400
30x = 1650 <<divide both sides by 30
x = 55.
Therefore, there are 55 large boxes
120 - x = small boxes
120 - 55 = 65 small boxes.
Hope this is the answer that you are looking for.
Let me know if you need more help next time!

6 0
3 years ago
Solve the system by substitution.<br> 10x + 5y = -50<br> y = -x
Pie

Answer:

(1,-12)

Step-by-step explanation:

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5y=-60

y=-12

10x-60=-50

10x=10

x=1

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Sindrei [870]

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Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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Please help me with this and please give me the right answer it’s due tommorow
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First, look and compare at the decimal places in brackets ( ) .

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