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polet [3.4K]
3 years ago
13

-3(x - 1) + 8(x - 3) = 6x + 7 - 5x Please helppp

Mathematics
1 answer:
Levart [38]3 years ago
6 0

Answer:

x=7

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

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If x is a negative number , what is true about -x plz help me thanks
kodGreya [7K]
If the only thing we know about x is that it is negative, we only know that -x will always be positive.
8 0
3 years ago
Read 2 more answers
Select the correct answer.
yulyashka [42]

Answer:

Option D is correct.

Volume=\frac{8}{27}\ cubic\ yard

Step-by-step explanation:

Let V be the volume of hay in each stack

Given:

Length of the each stack is \frac{2}{3}\ yard

And Jay stores hay in cubic stacks on his farm.

The volume of the cone is.

Volume\ of\ cone = (side)^{3}

Now, we substitute value of length of stack in above equation.

V=(\frac{2}{3})^{3}

V=\frac{2^{3}}{3^{3}}

V=\frac{8}{27}\ cubic\ yard

Therefore, the volume of hay in each stack is V=\frac{8}{27}\ cubic\ yard

3 0
3 years ago
The scale on a map shows that 10 kilometers is represented by 4 centimeters. Which proportion can be used to find the actual dis
Illusion [34]
10/4=x/20
Your answer will be x=50 kilometers
3 0
3 years ago
Read 2 more answers
02:23:02
lions [1.4K]

Answer:

(x + 2) \:  and  \: (x-6)

Step-by-step explanation:

{x}^{2}  - 14 - 12

{x}^{2}  + 2x - 6x - 12

x(x + 2) - 6(x + 2)

(x  + 2)(x  - 6)

<h3>Hope it is helpful....</h3>
4 0
3 years ago
Suppose a family has three children of different ages. We assume that all combinations of boys and girls are equally likely. (a)
Ivan

Answer:

a) There are 8 possible combinations and each probability is 1/8.

b) The probability that it is a boy given that there are two girls is 3/8

Step-by-step explanation:

a) The sample space is given by:

BBB (3 boys)

BBG (Boy, boy, girl)

BGB (Boy, girl, boy)

BGG (Boy, girl, girl)

GBB (girl, boy, boy)

GBG (girl, boy, girl)

GGB (girl, girl, boy)

GGG (3 girls)

The probability of each combination is the same:

P(BBB)=P(B∩B∩B)=\frac{1}{2} \frac{1}{2} \frac{1}{2}=\frac{1}{8}

2) There are three possible combinations in which there are 2 girls and 1 boy:

BGG, GBG, GGB

So the probability is given by:

P(BGG ∪ GBG ∪ GGB)=\frac{1}{2} \frac{1}{2} \frac{1}{2}+\frac{1}{2} \frac{1}{2} \frac{1}{2}+\frac{1}{2} \frac{1}{2} \frac{1}{2}=\frac{3}{8}

6 0
3 years ago
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