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3 years ago

The exact solution to the equation x^3 = 125 is +5 true or false

Mathematics

2 answers:

pickupchik [31]3 years ago

8 0

Answer:

True

Step-by-step explanation:

because 5^3 = 125

Natasha2012 [34]3 years ago

5 0

Answer:

True

Step-by-step explanation:

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Leilani dropped an acorn from her tree house. It took 1.1 seconds to hit the ground below. Find the height in feet from which sh

ratelena [41]

Your answer is 0.605

3 0

3 years ago

Please let me know the correct answer.

NNADVOKAT [17]

Set h to 640 and solve for t:

640 = -490t^2 + 1120t

Subtract 640 from both sides:

-490t^2 + 1120t - 640 = 0

The formula to solve a quadratic equation is:

x = -b -/+ sqrtroot (b^2-4ac)/(2a) where a = -490, b = 1120 and c = -640

Solve:

x = -1120 -/+ sqrtroot (1120^2-4(-490)(-640) )/ 2(-490)

x = 8/7 = 1.1428 = 1.14

Time was 1.14 seconds

4 0

3 years ago

What is the smallest subset that 46 belongs to

xeze [42]

Answer:

Natural/Counting Numbers

Step-by-step explanation:

It is the smallest subset a number can classify into. It is all of the numbers from 1 to positive infinity.

7 0

3 years ago

Help me please people it’s the last question

DochEvi [55]

Answer:

1 m³

Step-by-step explanation:

first find volume of smaller cubes

V = lwh

S = 1/3*1/3*1/3

S = 1/27

find volume of large cube. there are 27 smaller cubes.

V = 27S

V = 27(1/27)

V = 1

S: volume of small cube

V: volume of large cube

6 0

3 years ago

Read 2 more answers

Help ASAP show work please thanksss!!!!

Llana [10]

Answer:

$\displaystyle log_\frac{1}{2}(64)=-6$

Step-by-step explanation:

<u>Properties of Logarithms</u>

We'll recall below the basic properties of logarithms:

$log_b(1) = 0$

Logarithm of the base:

$log_b(b) = 1$

Product rule:

$log_b(xy) = log_b(x) + log_b(y)$

Division rule:

$\displaystyle log_b(\frac{x}{y}) = log_b(x) - log_b(y)$

Power rule:

$log_b(x^n) = n\cdot log_b(x)$

Change of base:

$\displaystyle log_b(x) = \frac{ log_a(x)}{log_a(b)}$

Simplifying logarithms often requires the application of one or more of the above properties.

Simplify

$\displaystyle log_\frac{1}{2}(64)$

Factoring $64=2^6$ .

$\displaystyle log_\frac{1}{2}(64)=\displaystyle log_\frac{1}{2}(2^6)$

Applying the power rule:

$\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}(2)$

Since

$\displaystyle 2=(1/2)^{-1}$

$\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}((1/2)^{-1})$

Applying the power rule:

$\displaystyle log_\frac{1}{2}(64)=-6\cdot log_\frac{1}{2}(\frac{1}{2})$

Applying the logarithm of the base:

$\mathbf{\displaystyle log_\frac{1}{2}(64)=-6}$

5 0

3 years ago