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3 years ago

Hep me with this question will give brainliest

Mathematics

1 answer:

ad-work [718]3 years ago

8 0

Answer:

a) $f(x) = x + 9$

b) 59 positive workers (FOR DAY 70)

c) Day 10

Step-by-step explanation:

X = Days

Y = Positive workers

You might be interested in

Write a recursive formula for the sequence 7, 4, 1, –2, –5, .... Then find the next term. (1 point) an = an–1 – 3, where a1 = –8

Anvisha [2.4K]

4 = 7 - 3

1 = 4 - 3

-2 = 1 - 3

-5 = -2 - 3

=> An = A (n-1) - 3, where A1 = 7

The next term is A6 = A5 - 3 = - 5 - 3 = - 8

So the answer is the fourth option.

3 0

3 years ago

Read 2 more answers

Which of the following is a terminating decimal?

prisoha [69]

A terminated decimal does not continue forever. If there is a line above a set amount of numbers, it is not a terminated decimal as it means those numbers go on forever.

In this case, C) 10.101 is your answer, as it does not continue forever.

hope this helps

7 0

3 years ago

Mrs.Galicia bought a condo for 62,000. Assuming that’s its value will appreciate 4% per year, how much will the condo be worth i

OverLord2011 [107]

D.
The equation would look like this
62,000(1+.04)^6

7 0

3 years ago

22. An employee joined a company in 2017 with a starting salary of $50,000. Every year this employee receives a raise of $1000 p

Setler79 [48]

Answer:

(a) The recurrence relation for the salary is

$S_{n+1}=1.05*S_n+1000\\\\S_0=50000$

(b) The salary 25 years after 2017 will be $217044.85.

Step-by-step explanation:

We can define the next year salary $S_{n+1}$ as

$S_{n+1}=S_n+1000+0.05*S_n=1.05*S_n+1000$

wit S0=$50000

If we extend this to 2 years from 2017 (n+2), we have

$S_{n+2}=1.05*S_{n+1}+1000=1.05*(1.05*S_n+1000)+1000\\S_{n+2} =1.05^2*S_n+1.05*1000+1000\\S_{n+2}=1.05^2*S_n+1000*(1.05^1+1)$

Extending to 3 years (n+3)

$S_{n+3}=1.05*S_{n+2}+1000=1.05(1.05^2*S_n+1000*(1.05^1+1))+1000\\\\S_{n+3}=1.05^3S_n+1.05*1000*(1.05^1+1)+1000\\\\S_{n+3}=1.05^3*S_n+1000*(1.05^2+1.05^1+1)$

Extending to 4 years (n+4)

$S_{n+4}=1.05*S_{n+3}+1000=1.05*(1.05^3*S_n+1000*(1.05^2+1.05^1+1))+1000\\\\S_{n+4}=1.05^4S_n+1.05*1000*(1.05^2+1.05^1+1))+1000\\\\S_{n+4}=1.05^4S_n+1000*(1.05^3+1.05^2+1.05^1+1.05^0)$

We can now express a general equation for S_n (salary at n years from 2017)

$S_n=1.05^nS_0+1000*\sum_{0}^{n-1}1.05^n$

The salary at 25 years from 2017 (n=25) will be

$S_{25}=1.05^{25}S_0+1000*\sum_{0}^{24}1.05^i\\\\S_{25}=3.386*50000+1000*47.72=217044.85$

8 0

4 years ago

This is a record of a marble being rolled along the ground. What was the marble's average speed for this entire trip? 1.5 m/s 15

ozzi

Answer:

1.486713333333333

Step-by-step explanation:

Step 1:

Add all 4 together.

1.5 + 15 + 0.67056 + 0.67

Step 2:

Divide by 4.

17.84056 ÷ 4

1.5 mph = 0.67056 m/s

6 0

3 years ago