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qaws [65]
3 years ago
11

One number is 1 less than a second number. twice the second number is 12 less than 3 times the first. find the two numbers

Mathematics
2 answers:
Alchen [17]3 years ago
5 0
The two numbers are 15 and 14
musickatia [10]3 years ago
3 0
A = b-1
2b=3a - 12

2b = 3(b-1) -12
2b = 3b - 3 -12
b = 15  a= 14
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HELP PLEASE THIS IS IMPORTANT- 10 points
wel
9) x= -17
10) n=0
11) x=-3
12) x=-21
3 0
3 years ago
Which set of ordered pairs could be generated by an exponential function?
devlian [24]

<u>ANSWER</u>

(0, 1), (1, 3), (2, 9), (3, 27)

<u>EXPLANATION</u>

The first and third options are completely out because the y-value of an exponential function is never zero.

For the second option the y-values has no geometric pattern or common ratio.

For the last option, we can observe the following pattern

1 =  {3}^{0}

{3}^{1}  = 3

{3}^{2}  = 9

{3}^{3}  = 27

:

:

{3}^{x}  = y

The correct choice is the last option

7 0
3 years ago
Read 2 more answers
Help please
Vadim26 [7]
<span>✡ </span>Answer: 75; 100-25-5 ✡


- - To solve this you are going to subtract.
Because you are taking away apples, in this case eating them

- - So: 100-20-5

Answer: 75

✡Hope this helps!<span>✡</span>





7 0
3 years ago
Read 2 more answers
What the equation of this graph?? I need help
yuradex [85]
X = 3

and

formula -

(y-y1)/(x-x1) = (y2-y1)/(x2-x1)

(x1,y1) = (4,1)
(x2,y2) =( 5,3)

(y-1)/(x-4) = (3-1)/(5-4)

y-1/x-4 = 2/1

y-1 = 2x - 8

y = 2x - 7

the solution will be x= 3 and y = -1
6 0
3 years ago
Solve the equations for all values of x by completing the square x^2+62=-16x
lorasvet [3.4K]

Answer:

x =  \sqrt{2} - 8\\x =  -\sqrt{2} - 8

Step-by-step explanation:

To complete the square, we first have to get our equation into ax^2 + bx = c form.

First we add 16x to both sides:

x^2 + 16x + 62 = 0

And now we subtract 62 from both sides.

x^2 + 16x = -62

We now have to add (\frac{b}{2})^2 to both sides of the equation. b is 16, so this value becomes (16\div2)^2 = 8^2 = 64.

x^2 + 16x + 64 = -62+64

We can now write the left side of the equation as a perfect square. We know that x+8 will be the solution because 8\cdot8=64 and 8+8=16.

(x+8)^2 = -62 + 64

We can now take the square root of both sides.

x+8 = \sqrt{-62+64}\\\\ x+8 = \pm \sqrt{2}

We can now isolate x on one side by subtracting 8 from both sides.

x = \pm\sqrt{2} - 8

So our solutions are

x =  \sqrt{2} - 8\\x =  -\sqrt{2} - 8

Hope this helped!

4 0
3 years ago
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