Question

In the standard (x, y) coordinate plane, what is the distance, in coordinate units, between (-3, -2) and (5, 5)?

Answer 1

Answer:

10.630

Step-by-step explanation:

$\sqrt(x_{2} -x_{1})^{2} + (y_{2} -y_{1})^{2}$

$\sqrt( 5-(-3)^{2} + (5- (-2)^{2}$

(5 - ( - 3)^2 = 64

(5 - ( -2)^2 = 49

49 + 64

113

$\sqrt113$

10.630

I hope this helps