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allochka39001 [22]
3 years ago
9

Can some one plz help me with these 2 problems

Mathematics
1 answer:
natulia [17]3 years ago
7 0

<em>The</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>of</em><em> </em><em>1</em><em>s</em><em>t</em><em> </em><em>question</em><em> </em><em>is</em><em> </em><em>(</em><em>4</em><em>*</em><em>3</em><em>0</em><em>)</em><em>+</em><em>(</em><em>4</em><em>*</em><em>8</em><em>)</em><em>.</em><em>[</em><em>Option</em><em> </em><em>C</em><em>]</em>

<em>The</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>of</em><em> </em><em>2</em><em>n</em><em>d</em><em> </em><em>question</em><em> </em><em>is</em><em> </em><em>3</em><em>5</em><em>.</em>

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>

<em>H</em><em>ope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em>

<em>G</em><em>ood</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em><em>.</em><em>.</em><em>.</em>

<em>~</em><em>p</em><em>r</em><em>a</em><em>g</em><em>y</em><em>a</em>

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Find the exact solutions to 2x^2=5x-1 by using the quadratic formula
Luda [366]

Solve the equation for  x  by finding  a ,  b , and  c of the quadratic then applying the quadratic formula

Exact form:

x =  5 ± √ 17

     4

Decimal:

x =  2.28077640 … , 0.21922359

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3 0
3 years ago
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Whats a quadratic equation that has the roots of 6 and negative 9
Komok [63]

Answer:

x^2-3x-54

Step-by-step explanation:

(x+6)(x-9)     Setup the roots

x^2-9x+6x-54   FOIL out the terms

x^2-3x-54    Add like terms together

5 0
3 years ago
Great tennis players use Hexrackets. There if you use a Hexracket, you are a great tennis nyer.
34kurt

Answer:

The conclusion is invalid.

The required diagram is shown below:

Step-by-step explanation:

Consider the provided statement.

Great tennis players use Hexrackets. Therefore, if you use a Hexracket, you are a great tennis player.

From the above statement we can concluded that Great tennis players use Hexrackets. But it may be possible that some people who use a haxracket are not great tennis player.

Therefore, the conclusion is invalid.

The required diagram is shown below:

8 0
3 years ago
What is equivalent to 5-squared3
pentagon [3]

Answer: 125

Step-by-step explanation:

5^3=5*5*5=125

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5 0
3 years ago
An electronics company produces​ transistors, resistors, and computer chips. Each transistor requires 3 units of​ copper, 1 unit
padilas [110]

Answer:

An electronics company can be produce 350 transistors and 340 computer chips, they can´t produce resistors.

Step-by-step explanation:

1. We will name the variables for transistors, resistors and the computer chips.

a = Transistors

b= Resistors

c = Computer chips

2. We propose three linear equations, one for the copper, one for the zinc and one for the glass.

\left \{ {{3a+3b+2c=1730} \atop {a+2b+c=690}}\atop {2a+b+2c=1380}} \right.

3. We write the matrix form as Ax=d

A=\left(\begin{array}{ccc}3&3&2\\1&2&1\\2&1&2\end{array}\right)

x=\left(\begin{array}{ccc}a\\b\\c\end{array}\right)

A=\left(\begin{array}{ccc}1730\\690\\1380\end{array}\right)

With this formula the solution of x is x=\frac{d}{A} or x=A^{-1}d

4. We will find the inverse matrix A^{-1} using the formula:

A^{-1} = \frac{1}{detA} (C_{A})^{T}

a. det A

det A=\left[\begin{array}{ccc}3&3&2\\1&2&1\\2&1&2\end{array}\right] =3*(4-1)-3*(2-2)+2*(1-4)=9-0-6=3

b. (C_{A})^{T}

C_{A}=\left(\begin{array}{ccc}4-1&.(2-2)&1-4\\-(6-2)&6-4&-(3-6)\\3-4&-(3-2)&6-3\end{array}\right)

C_{A}=\left(\begin{array}{ccc}3&.0&-3\\-4&2&3\\-1&-1&3\end{array}\right)

(C_{A}) ^T=\left(\begin{array}{ccc}3&0&-3\\-4&2&3\\-1&-1&3\end{array}\right)^T

(C_{A}) ^T=\left(\begin{array}{ccc}3&-4&-1\\0&2&-1\\-3&3&3\end{array}\right)

c.A^{-1}

A^{-1}=\frac{1}{3} \left(\begin{array}{ccc}3&-4&-1\\0&2&-1\\-3&3&3\end{array}\right)

5. As x=\frac{d}{A} or x=A^{-1}d, the solution of x is:

x=\frac{1}{3}\left(\begin{array}{ccc}3&-4&-1\\0&2&-1\\-3&3&3\end{array}\right)\left(\begin{array}{ccc}1730\\690\\1380\end{array}\right)

x=\frac{1}{3}\left(\begin{array}{ccc}(3*1730)+(-4*690)+(-1*1380)\\(0*1730)+(2*690)+(-1*1380)\\(-3*1730)+(3*690)+(3*1380)\end{array}\right)

x=\frac{1}{3}\left(\begin{array}{ccc}1050\\0\\1020)\end{array}\right)

X=\left[\begin{array}{ccc}350\\0\\340\end{array}\right]

<u><em>Therefore:</em></u>

<u><em>a= 350 Transistors</em></u>

<u><em>b=0 Resistors</em></u>

<u><em>c=340 Computer chips</em></u>

4 0
3 years ago
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