Answer: The z-scores for a woman 6 feet tall is 2.96 and the z-scores for a a man 5'10" tall is 0.25.
Step-by-step explanation:
Let x and y area the random variable that represents the heights of women and men.
Given : The heights of women aged 20 to 29 are approximately Normal with mean 64 inches and standard deviation 2.7 inches.
i.e.

Since , 
Then, z-score corresponds to a woman 6 feet tall (i.e. x=72 inches).
[∵ 1 foot = 12 inches , 6 feet = 6(12)=72 inches]

Men the same age have mean height 69.3 inches with standard deviation 2.8 inches.
i.e.

Then, z-score corresponds to a man 5'10" tall (i.e. y =70 inches).
[∵ 1 foot = 12 inches , 5 feet 10 inches= 5(12)+10=70 inches]

∴ The z-scores for a woman 6 feet tall is 2.96 and the z-scores for a a man 5'10" tall is 0.25.
So, We Need To Examine The Problem. So, We Know That We Need To Find The Volume Of A Rectangular Prism. We Also Know That The Dimensions Are 4.9 • 3.8 • 5.4.
So, We Need To Remember The Formula For Volume Of A Rectangular Prism.
V = B • W • H
So, we need to plug in the known values.
V = 4.9 • 3.8<span> • 5.4.
So, Lets Solve.
4.9 • 3.8 = 18.62
18.62 * 5.4 = 100.548 cm²
Now We Have:
V = 100.548cm²
It Rounds To 100.5cm²</span>
The constraint on time is
.. 75W +15M ≥ 300 . . . . . . . minutes
The constraint on paper is
.. 3W +M ≤ 20 . . . . . . . . . . . sheets of paper
Answer:
D
Step-by-step explanation:
Brainliest?