3 years ago

A body is accelerated continuously. What is the form of the graph?

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1 answer:

Marat540 [252]3 years ago

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Do you have a picture of the graph?

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$\text{Hi there! :)}$

$\large\boxed{f'(2) = -\frac{16}{27} }$

$f'(x) = \frac{(5 + x^{2} )(-2x) - (7 - x^{2} )(2x)}{(5+x^{2})^{2} } \\\\f'(x) = \frac{-10x-2x^{3}- 14x + 2x^{3} }{(5+x^{2})^{2} } \\\\f'(x) = \frac{-24x}{(5+x^{2})^{2} }\\\\ \text{Solve for the derivative at f'(2) using substitution:}\\\\f'(2) = \frac{-24(2)}{(5+2^{2})^{2} } \\\\f'(2) = \frac{-48}{81} \\\\\text{Simplify:}\\\\f'(2) = -\frac{16}{27}$