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Leno4ka [110]
3 years ago
12

A bicycle company has designed and built a new model of sports bicycle. They have determined that the profit for the sale of the

bicycles can be modeled by the function:
P(x) = -2x(squared) + 920x + 84,000

Where x is the price of each bicycle. Which of the following is a sale price for the bicycles that will allow the company to achieve a profit of $21,800?


A) $230
B) $250
C) $210
D) $270
Mathematics
1 answer:
ycow [4]3 years ago
4 0
The answer would be c)$120
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Need math help asap please! :/ thanks
Dominik [7]

The rule to remember about generating the perpendicular family to a line is we swap the coefficients on and x and y, remembering to negate one of them. Then the constant is set directly from the intersecting point.


So we have


y = 3x + 2


-3x + 1y = 2


Swapping and negating gets the perpendiculars; the constant is as yet undetermined.


1x + 3y = constant


Since we want to go through (0,2), we could have just written


x + 3y = 0 + 3(2) = 6


3y = -x + 6


y = (-1/3) x + 2


Third choice


5 0
3 years ago
HELP ASAP PLEASE!!!!!!
Volgvan
I think b am not sure
3 0
3 years ago
Read 2 more answers
The cost y to rent a tent is proportional to x days. if it costs $56 to rent a tent for 7 days what is the formula
Alona [7]
Probably y = 8x. 56 = 8(7), so that works. Without more data, I couldn't say if it could be something else, so that's what I go with.
4 0
2 years ago
. Mrs. Rojas deposited $8000 into an account paying 4% interest annually. After 8 months Mrs. Rojas withdrew the $6000 plus inte
Mashcka [7]

well, keeping in mind that a year has 12 months, that means that 8 months is 8/12 of a year, when Mrs Rojas pull her money out.

~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\to \frac{8}{12}\dotfill &\frac{2}{3} \end{cases} \\\\\\ A=6000[1+(0.04)(\frac{2}{3})]\implies A=6000\left( \frac{77}{75} \right)\implies A=6160

well, she put in 6000 bucks, got back 160 extra, that's the interest earned in the 8 months.

what if she had left her money for 1 whole year, then

~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\dotfill &1 \end{cases} \\\\\\ A=6000[1+(0.04)(1)]\implies A=6240

so had she left it in for a year, she'd have gotten 6240, namely 240 in interest, well, what fraction of a year's interest was earned? or worded differently, what fraction is 160(8 months) of 240(1 year)?

\cfrac{\stackrel{\textit{for 8 months}}{160}}{\underset{\textit{for 12 months}}{240}}\implies \cfrac{2}{3}

4 0
2 years ago
Write an equation in the form y= mx + b to represent the graph.
mixas84 [53]
Y=x-2





..........................
.
5 0
3 years ago
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