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3 years ago

Which linear inequality is represented by the graph?

Mathematics

1 answer:

Dovator [93]3 years ago

3 0

Answer:

The answer to your question is the second choice (y ≥ 1/3x - 1)

Step-by-step explanation:

Process

1.- Find two points of the graph

A (0, -1)

B (3, 0)

2.- Find the slope

m = (0 + 1)/(3 - 0)

m = 1/3

3.- Find the equation of the line

y - y1 = m(x - x1)

y + 1 = 1/3(x - 0)

y + 1 = 1/3x

y = 1/3x - 1

4.- Find the equation of the inequality

We need the upper part of the line so the inequality must be

y ≥ 1/3x - 1

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Alex_Xolod [135]

Answer:

A. x = 6.08, x = -0.58

Step-by-step explanation:

$\displaystyle \frac{2x}{x-4}-\frac{2x-5}{x^2-10x+24}=\frac{-3}{x-6}$

1. Factor the denominator.

$\displaystyle \frac{2x}{x-4}-\frac{2x-5}{(x-6)(x-4)}=\frac{-3}{x-6}$

2. Multiply the leftmost fraction by (x-6)/(x-6) to get common denominators.

$\displaystyle \Big ( \frac{x-6}{x-6} \Big ) \frac{2x}{x-4}-\frac{2x-5}{(x-6)(x-4)}=\frac{-3}{x-6}$

3. Simplify.

$\displaystyle \frac{2x^2-12x}{(x-4)(x-6)}-\frac{2x-5}{(x-6)(x-4)}=\frac{-3}{x-6}$

4. Combine like terms.

$\displaystyle \frac{2x^2-14x+5}{(x-4)(x-6)}=\frac{-3}{x-6}$

5. Multiply the right side of the equation by (x-4)/(x-4).

$\displaystyle \frac{2x^2-14x+5}{(x-4)(x-6)}=\frac{-3}{x-6} \Big ( \frac{x-4}{x-4} \Big )$

6. Simplify.

$\displaystyle \frac{2x^2-14x+5}{(x-4)(x-6)}=\frac{-3x+12}{(x-6)(x-4)}$

7. "Cancel" out the denominators because they are equivalent.

$2x^2-14x+5=-3x+12$

8. Set the equation equal to 0.

$2x^2-11x-7=0$

Quadratic formula:

$\displaystyle x = \frac{-b\pm \sqrt{b^2-4ac} }{2a}$

9. Factor using the quadratic formula.

$\displaystyle x = \frac{-(-11)\pm \sqrt{(-11)^2-4(2)(-7)} }{2(2)}$

10. Multiply and simplify.

$\displaystyle x = \frac{11 \pm \sqrt{177} }{4}$

11. Plug this into your calculator and solve for x.

$x=6.07603367 \approx 6.08$
$x=-0.57603367 \approx -0.58$

The correct answer is A. x = 6.08, x = -0.58.

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