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katen-ka-za [31]
3 years ago
11

PLZ HELP ASAP SOLVE SIMMILAR TRIANGLES

Mathematics
1 answer:
xxMikexx [17]3 years ago
8 0
By similarity of triangles we have the following equation:
 (x + 9) / (9) = (x) / (1)
 Clearing the value of x we have:
 (x + 9) = 9x
 Rewriting we have:
 9 = 9x-x
 9 = 8x
 x = 9/8
 x = 1,125
 Answer:
 
The value of x for this case is given by:
 
x = 1,125
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Help please!!! really really important​
Serga [27]

Answer:

42. Graph a

43. Not possible.

44. Graph e

45. Graph c

46. Graph b.

Step-by-step explanation:

42. 7x + 13 ≥ 55

⇒ x ≥ 6

So, it matches graph a.

43. 12x - 8 > 4(3x + 2)

⇒ 12x - 8 > 12x + 8

Hence, d. not possible.

44. \frac{x}{- 4} - 3 < - 1

⇒ \frac{x}{- 4} < 2

⇒ x > - 8

Hence, graph e matches.

45. - 4(- 2x + 3) ≤ 5 + 8x

⇒ 8x - 12 ≤ 5 + 8x

⇒ - 12 ≤ 5

This is true for all values of x, hence that matches graph c.

46. - 4(x + 3) > 8(x + 3)

⇒ - 4x - 12 > 8x + 24

⇒ 12x < - 36

⇒ x < - 3

Hence, graph b matches the situation. (Answer)

4 0
3 years ago
See the question below.
zheka24 [161]

your answer is B i hope this helpss

4 0
3 years ago
Read 2 more answers
A professor would like to test the hypothesis that the average number of minutes that a student needs to complete a statistics e
professor190 [17]

Answer:

\chi^2 =\frac{15-1}{25} 16 =8.96

The degrees of freedom are given by:

df = n-1 = 15-1=14

The p value for this case would be given by:

p_v =P(\chi^2

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not ignificantly lower than 5 minutes

Step-by-step explanation:

Information given

n=15 represent the sample size

\alpha=0.05 represent the confidence level  

s^2 =16 represent the sample variance

\sigma^2_0 =25 represent the value that we want to  verify

System of hypothesis

We want to test if the true deviation for this case is lesss than 5minutes, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 \geq 25

Alternative hypothesis: \sigma^2

The statistic is given by:

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

And replacing we got:

\chi^2 =\frac{15-1}{25} 16 =8.96

The degrees of freedom are given by:

df = n-1 = 15-1=14

The p value for this case would be given by:

p_v =P(\chi^2

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not ignificantly lower than 5 minutes

6 0
3 years ago
What is another name for &lt;1?
Oksanka [162]

Option A:

The another name for ∠1 is ∠JLK.

Solution:

How to Label Angles :

There are two main ways to label angles:

1. Give the angle name by a number or a lower case letters.

2. The second way to name the angle is indicating by the vertex.

Usually the angle is denoted by three letters.

First letter and the second letter denotes the arms of the angle and the middle of the letter denotes the angle (its vertex).

To find the another name for ∠1.

The arms of the angle are LJ and LK and the vertex is L.

So, the name of the angle is ∠JLK.

Middle letter is the actual angle.

Therefore the another name for ∠1 is ∠JLK.

Option A is the correct answer.

8 0
3 years ago
Plz Help!
Volgvan
The stack of cards are 1 inch tall all together taking up 8 inch’s (cubed)or half of the space
4 0
3 years ago
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