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qaws [65]
4 years ago
12

From the mid-1960s to the early 1990s, there was a slow but steady decline in SAT scores. For example, take the Verbal SAT. The

average in 1967 was about 543; by 1994, the average was down to about 499. However, the SD stayed close to 110. The drop in averages has a large effect on the tails of the distribution.
(a) Estimate the percentage of students scoring over 700 in 1967.
(b) Estimate the percentage of students scoring over 700 in 1994.
Mathematics
1 answer:
daser333 [38]4 years ago
5 0

Answer:

a) 7.68%

b) 3.38%

Step-by-step explanation:

(a) Estimate the percentage of students scoring over 700 in 1967.

The probability that a student scored over 700 in 1967 equals the area under the Normal curve with mean 543 and standard deviation 110 to the right of 700.

In<em> Excel </em> this value is found with the formula

=1-NORMDIST(700,543,110,1)

and in <em>OpenOffice Calc </em>

=1-NORMDIST(700;543;110;1)

<em> (NORMDIST(700;543;110;1) gives the area to the left of 700, so 1-NORMDIST(700;543;110;1) gives the area to the right of 700) </em>

and equals 0.07675

So, the percentage of students scoring over 700 in 1967 was 7.68%

(b) Estimate the percentage of students scoring over 700 in 1994.

The probability that a student scored over 700 in 1994 equals the area under the Normal curve with mean 499 and standard deviation 110 to the right of 700.

In <em>Excel</em>  this value is found with the formula

=1-NORMDIST(700,499,110,1)

and in <em>OpenOffice Calc </em>

=1-NORMDIST(700;499;110;1)

and equals 0.03383

So, the percentage of students scoring over 700 in 1994 was 3.38%

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You are collecting pairs of socks and toothbrushes for a local charity. After d days, you have collected (4d+5) pairs of socks a
Tcecarenko [31]

Answer: the expression that represents the total number of items that have been collected is

7d + 12

Step-by-step explanation:

You are collecting pairs of socks and toothbrushes for a local charity.

Total number of pairs of socks that you would have collected after d days is (4d+5)

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8 0
4 years ago
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REY [17]

Answer:

380

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8 0
3 years ago
Thanks for all your help
ELEN [110]
Around 15.16666. I hope this helps!
7 0
3 years ago
Read 2 more answers
Solution to the inequality 16x−33x&lt;37x+27.
astra-53 [7]

<em><u>The solution to the inequality is:</u></em>

x>\frac{-1}{2}

<em><u>Solution:</u></em>

Given inequality is:

16x-33x

We have to find the solution to given inequality

\mathrm{Add\:similar\:elements:}\:16x-33x=-17x

-17x

\mathrm{Subtract\:}37x\mathrm{\:from\:both\:sides}

-17x-37x

Simplify the above inequality

-54x

\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}

Remember that, change the inequality sign if you divide or multiply both sides by a negative number

If you divide or multiply both sides by a positive number,the inequality sign will not change

\left(-54x\right)\left(-1\right)>27\left(-1\right)\\\\54x>-27

\mathrm{Divide\:both\:sides\:by\:}54

\frac{54x}{54}>\frac{-27}{54}\\\\x>-\frac{1}{2}

Thus the solution to inequality is found

3 0
4 years ago
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