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Answer:
The correct answer for the given question is "Machine languages can be used to write programs that can run on any machine."
Explanation:
The machine language consist of binary digit i. e 0 and 1 .Computer can understand only the machine language .The machine language consist of code that is written in bits so it is used to express algorithms.When any program is compiled the compiler are converted into machine code so the machine language is produced by the compiler .
Machine language cannot used to write a program that run on any machine.
Answer:
// here is code in c++ to find the approx value of "e".
#include <bits/stdc++.h>
using namespace std;
// function to find factorial of a number
double fact(int n){
double f =1.0;
// if n=0 then return 1
if(n==0)
return 1;
for(int a=1;a<=n;++a)
f = f *a;
// return the factorial of number
return f;
}
// driver function
int main()
{
// variable
int n;
double sum=0;
cout<<"enter n:";
// read the value of n
cin>>n;
// Calculate the sum of the series
for (int x = 0; x <= n; x++)
{
sum += 1.0/fact(x);
}
// print the approx value of "e"
cout<<"Approx Value of e is: "<<sum<<endl;
return 0;
}
Explanation:
Read the value of "n" from user. Declare and initialize variable "sum" to store the sum of series.Create a function to Calculate the factorial of a given number. Calculate the sum of all the term of the series 1+1/1!+1/2!.....+1/n!.This will be the approx value of "e".
Output:
enter n:12
Approx Value of e is: 2.71828
Hello, you haven't provided the programing language in which you need the code, I'll explain how to do it using Python, and you can follow the same logic to make a program in the programing language that you need.
Answer:
1. # -*- coding: utf-8 -*-
2. #Python
3. class Calculator:
4. def add(self):
5. print(a + b)
6. def sub(self):
7. print(a - b)
8. def mul(self):
9. print(a * b)
10. def div(self):
11. print(a / b)
12.
13. obj = Calculator()
14. choice = 1
15. while choice != 0:
16. a = int(input("\nEnter first number: "))
17. b = int(input("Enter first number: "))
18.
19. print("\n0. EXIT")
20. print("1. DIVISION")
21. print("2. ADDITION")
22. print("3. SUBTRACTION")
23. print("4. MULTIPLICATION")
24.
25. choice = int(input("\nEnter your choice: "))
26. if choice == 1:
27. obj.div()
28. elif choice == 2:
29. obj.add()
30. elif choice == 3:
31. obj.sub()
32. elif choice == 4:
33. obj.mul()
34. else:
35. break
Explanation:
- From lines 1 to 12 we define the object with four methods, addition, subtraction, multiplication, and division. Each method contains the operation between two variables inside a print function
- On line 13 we instantiate our class
- On line 14 we declare the variable choice that is going to store the operation that the user wants to perform
- On line 15 we declare a while loop, this is going to keep running the program until the user wants to exit
- From line 16 to 18 we ask the user to enter two numbers
- From line 19 to 24 we print the possible operation, assigning a number for each operation, this indicates to the user what number to press for what operation
- On line 25 we ask the user for the operation
- From lines 26 to 35 we check the user input an accordingly we call the corresponding method to performs the operation
