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polet [3.4K]
3 years ago
7

A lamp outside a front door comes on automatically when it is dark, and when someone stands on the doormat outside the front doo

r. A pressure sensor under the mat changes from OFF (0) to ON (1) when someone stands on the doormat. The light sensor is ON (1) when it is light and OFF (0) when it is dark. Design a program to show what would happen to the lamp. Account for all possible scenarios by determining whether the pressure sensor and light sensor are ON or OFF. (HINT: Ask the user "Is it dark?" and "Is someone standing on the doormat outside the front door?")

Computers and Technology
1 answer:
Lena [83]3 years ago
8 0

Answer:

See explaination

Explanation:

#include <iostream>

#include <string>

using namespace std;

int main()

{

string raptor_prompt_variable_zzyz;

?? standing;

?? dark;

raptor_prompt_variable_zzyz ="Is it dark?";

cout << raptor_prompt_variable_zzyz << endl;

cin >> DARK;

if (DARK=="Yes")

{

raptor_prompt_variable_zzyz ="Is someone standing on the doormat outside the front door?";

cout << raptor_prompt_variable_zzyz << endl;

cin >> STANDING;

if (STANDING=="Yes")

{

cout << "LAMP IS ON" << endl; }

else

{

cout << "LAMP IS OFF" << endl; }

}

else

{

cout << "LAMP IS OFF" << endl; }

return 0;

}

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in java how do i Write a program that reads a set of integers, and then prints the sum of the even and odd integers.
hammer [34]

Answer:

Here is the JAVA program:

import java.util.Scanner; //to take input from user

public class Main{

public static void main(String[] args) { //start of main function

Scanner input = new Scanner(System.in); // creates Scanner class object  

       int num, integer, odd = 0, even = 0; //declare variables

       System.out.print("Enter the number of integers: "); //prompts user to enter number of integers

       num = input.nextInt(); //reads value of num from user

       System.out.print("Enter the integers:\n"); //prompts user to enter the integers

       for (int i = 0; i < num; i++) { //iterates through each input integer

           integer = input.nextInt(); // reads each integer value

               if (integer % 2 == 0) //if integer value is completely divisible by 2

                   even += integer; //adds even integers

               else //if integer value is not completely divisible by 2

                   odd += integer;  } //adds odd integers

           System.out.print("Sum of Even Numbers: " + even); //prints the sum of even integers

           System.out.print("\nSum of Odd Numbers: " + odd);//prints the sum of odd integers

           }}

Explanation:

The program is explained in the comments mentioned with each line of the code. I will explain the logic of the program with the help of an example.

Suppose user wants to input 5 integers. So,

num = 5

Suppose the input integers are:

1, 2 , 3, 4, 5

for (int i = 0; i < num; i++)  is a for loop that has a variable i initialized to 0. The condition i<num is true because i=0 and num=5 so 0<5. Hence the statements inside body of loop execute.

At first iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 1

if (integer % 2 == 0) checks if integer is completely divisible by 2. The modulo operator is used which returns the remainder of the division and if this remainder is equal to 0 then it means that the integer is completely divisible by 2 and if the integer is completely divisible by 2 then this means the integer is even. 1%2 returns 1 so this means this condition evaluates to false and the integer is not even. So the else part executes:

odd += integer;   this becomes:

odd = odd + integer

odd = 1

Now the value of i is incremented to 1 so i=1

At second iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 2

if (integer % 2 == 0) checks if integer is completely divisible by 2. 2%2 returns 0 so this means this condition evaluates to true and the integer is even. So

even += integer;   this becomes:

even= even+ integer

even = 2

Now the value of i is incremented to 1 so i=2

At third iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 3

if (integer % 2 == 0) checks if integer is completely divisible by 2. 3%2 returns 1 so this means this condition evaluates to false and the integer is odd. So

odd += integer;   this becomes:

odd= odd + integer

odd= 1 + 3

odd = 4

Now the value of i is incremented to 1 so i=3

At fourth iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 4

if (integer % 2 == 0) checks if integer is completely divisible by 2. 4%2 returns 0 so this means this condition evaluates to true and the integer is even. So

even+= integer;   this becomes:

even = even + integer

even = 2 + 4

even = 6

Now the value of i is incremented to 1 so i=4

At fifth iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 5

if (integer % 2 == 0) checks if integer is completely divisible by 2. 5%2 returns 1 so this means this condition evaluates to false and the integer is odd. So

odd+= integer;   this becomes:

odd= odd+ integer

odd= 4 + 5

odd = 9

Now the value of i is incremented to 1 so i=5

When i=5 then i<num condition evaluate to false so the loop breaks. The next two print statement prints the values of even and odd. So

even = 6

odd = 9

Hence the output is:

Sum of Even Numbers: 6                                                                                                           Sum of Odd Numbers: 9  

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A __________ acts as separate network that rests outside the secure network perimeter so untrusted users can access web servers
pychu [463]
Firewall
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How do we add questions on sam Blockly?​
Blizzard [7]

Answer:

I do not know that answer

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According to the order of operation in Excel: a. Excel performs exponentiation, then multiplication, then division, then subtrac
Ilya [14]

Answer:

Option is b is correct answer. Excel performs exponentiation, then multiplication and division, then addition, and subtraction, it is correct order of operation in Excel. It is important to remember when you write any formula in Excel having different mathematical operators like +/ -/ ^/  etc, it follows a specific order and performs calculations in specific order which is termed as order of operator precedence. Each of mathematical operator has its precedence and executes in a special order set by Excel.

Explanation:

  • As we already know order of precedence of each mathematical operator is different in Excel. The order of operations for Excel is as follows:

  • Evaluate elements in parentheses.
  • Evaluate 'ranges' ().  
  • Evaluate 'intersections' (empty spaces).  
  • Evaluate 'unions' (,).
  • Perform negation (-).  
  • determine percentages (%).  
  • Perform exponentiation (^).  
  • Perform multiplication (*) and division (/), both are of equal precedence.  
  • Perform addition (+) and subtraction (-), both are of equal precedence.  
  • Evaluate text operators like (&).  
  • Perform comparisons like (=, <>, <=, >=).

 

Answer details  

Grade: Middle

Subject: Computers and Technology

Chapter: Order of precedence of mathematical operators

Keywords: precedence in Excel, operators precedence etc

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3 years ago
Write a program that initializes a string variable and prints the first three characters, followed by three periods, and then th
d1i1m1o1n [39]

firstly we have to initialize the variable, means to give variable a value and then print the statement

string = "fahadisahadam"

print(string[:3]+"..."+string[-3:])

string is a data type that contains two or more characters.

means the string is fahadisahadam so the print will print first three characters. follow by three periods(...) and then last three characters.

The output will be:

fah...dam

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