I assume that you mean the *numeral* 7, the written for of the number in a common font.
<span>This has no symmetry. In an extreme case, with the top extended to be the same length as the slant stroke, and restricting both to simple line segments, *then* you would have symmetry across a line bisecting the angle.</span>
Without values for the other variables, I assume you're asking for a literal equation.
12y+d=-19y+t
31y+d=t
31y=-d+t
y=(-d+t)/31
F(x)=-2e^x
x=3
f(3)=-2e^3
pemdas so exponents first
e^3
e=2.718281828454590
cube that
20.0855
now we have
-2 times 20.0855=-40.1711
answer should be -40.1711
(I see what you did wrong, if -6=-2 times e^3, divide -2, 3=e^3, maybe you just put -2 times 3 by mistake)
Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
Answer:
g(q) = 5/8q
Step-by-step explanation:
-7q + 12r = 3q - 4r
Add 4r to each side
-7q + 12r+4r = 3q - 4r+4r
-7q +16r = 3q
Add 7q to each side
-7q+7q +16r = 3q+7q
16r = 10q
Divide each side by 16
16r/16 = 10q/16
r = 5q/8
g(q) = 5/8q
