Step-by-step explanation:
Domain of a rational function is everywhere except where we set vertical asymptotes. or removable discontinues
Here, we have
First, notice we have x in both the numerator and denomiator so we have a removable discounties at x.
Since, we don't want x to be 0,
We have a removable discontinuity at x=0
Now, we have
We don't want the denomiator be zero because we can't divide by zero.
so
So our domain is
All Real Numbers except-2 and 0.
The vertical asymptors is x=-2.
To find the horinzontal asymptote, notice how the numerator and denomator have the same degree. So this mean we will have a horinzontal asymptoe of
The leading coeffixent of the numerator/ the leading coefficent of the denomiator.
So that becomes
So we have a horinzontal asymptofe of 2
Answer: 315,392
Step-by-step explanation: this took me some time but I multiplied multiple times each time and I got this I hope it’s correct.
Btw I multiplied 2 times 8 then multipled with 11 then multipied 172 times 8 then multiplied by 14 and got 19,712. Then, I multiplied 19,712 by 16 and got 315,392
I had to edit cause I miscalculated :/ anyways I hope this is correct
Answer (depending if the fraction is positive or negative):
- x ≥ 18
- x ≤ -18
Step-by-step explanation:
If the fraction is positive:
- Write it out:
- Multiply each side by 6 to cancel out the 6 under x. It should now look like this: x ≥ 18
If the fraction is negative:
- Write it out:
- Multiply each side by -6 to cancel out the -6 under x. It should now look like this: x ≤ -18
I hope this helps!
Answer:
2
Step-by-step explanation:
the mode is the one that appears the most, most common one