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aleksandrvk [35]
3 years ago
14

If m∠SRQ = 6x + 2 and m∠QRP = 2x + 10, find the value of x . *

Mathematics
1 answer:
Neko [114]3 years ago
7 0

Answer:

for m∠SRQ x =  3

for m∠QRP x = 5

Step-by-step explanation:

1. 6x +2. 6 is being multiplied by a number so to find that number we do teh opposite

6x/2 = 3

drop the x then u have x = 3

2. 2x+10. 2 is being muliplied by a number so to find that number we do teh opposite

10/2x = 5

drop the x then u have x = 5

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Step-by-step explanation:

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\Delta s = \frac{213^{\circ}}{360^{\circ}}\cdot 2\pi \cdot r

\Delta s = \frac{71\pi}{60}\cdot r

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Determine if the following table represents a quadratic function.
snow_tiger [21]

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<em>The options are not visible enough (See Explanation)</em>

Step-by-step explanation:

Given

x:-  1   || 2   || 3   || 4   || 5

y:-  13 || 22 || 37 || 58 || 85

Required

Determine if the function is quadratic

Calculate the difference between the values of y

Difference = 22 - 13 = 9

Difference = 37 - 22 = 15

Difference = 58 - 37 = 21

Difference = 85 - 58 = 27

<em>The resulting difference are: 9 || 15 || 21 ||  27</em>

Next; Calculate the difference between the difference of values of y

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