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Marizza181 [45]
3 years ago
6

Please I need help !!

Mathematics
2 answers:
kicyunya [14]3 years ago
6 0

Answer:

y = -1x + 1

Step-by-step explanation:

Effectus [21]3 years ago
4 0

Answer:

y = -1x + 1

Step-by-step explanation:

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3x - 5 = 1/2x + 2x solve the equation and please show your work im confused
Monica [59]

Answer:I searched it up on go

Step-by-step explanation:and I got 5x-5+ x/2

8 0
3 years ago
Let M be the set of all nxn matrices. Define a relation on won M by A B there exists an invertible matrix P such that A = P BP S
Sophie [7]

Answer:

Recall that a relation is an <em>equivalence relation</em> if and only if is symmetric, reflexive and transitive. In order to simplify the notation we will use A↔B when A is in relation with B.

<em>Reflexive: </em>We need to prove that A↔A. Let us write J for the identity matrix and recall that J is invertible. Notice that A=J^{-1}AJ. Thus, A↔A.

<em>Symmetric</em>: We need to prove that A↔B implies B↔A. As A↔B there exists an invertible matrix P such that A=P^{-1}BP. In this equality we can perform a right multiplication by P^{-1} and obtain AP^{-1} =P^{-1}B. Then, in the obtained equality we perform a left multiplication by P and get PAP^{-1} =B. If we write Q=P^{-1} and Q^{-1} = P we have B = Q^{-1}AQ. Thus, B↔A.

<em>Transitive</em>: We need to prove that A↔B and B↔C implies A↔C. From the fact A↔B we have A=P^{-1}BP and from B↔C we have B=Q^{-1}CQ. Now, if we substitute the last equality into the first one we get

A=P^{-1}Q^{-1}CQP = (P^{-1}Q^{-1})C(QP).

Recall that if P and Q are invertible, then QP is invertible and (QP)^{-1}=P^{-1}Q^{-1}. So, if we denote R=QP we obtained that

A=R^{-1}CR. Hence, A↔C.

Therefore, the relation is an <em>equivalence relation</em>.

4 0
3 years ago
Need answer to. Add 3x-3and4x^2-6x
Dahasolnce [82]
3x-3+4x^2-6x
4x^2-6x+3x-3 (arrange them in order)
4x^2-3x-3

do u want  more simplified form ?
7 0
3 years ago
Convert from fraction to decimal 7/9
nydimaria [60]
7.90 not 100 percent sure though.
5 0
3 years ago
. A survey found that women spend on average $146 on beauty products during the summer months. Assume the standard deviation is
arsen [322]

Answer:

69.1% of the woman spend less than $160

Step-by-step explanation:

Assuming that the random variable X= spend on beauty products by women during summer months distributes normally , then using the standarized variable Z:

Z= (X - mean / st. dev) = (160.00-146 )/28 = 0.5

then using normal probability tables for Z:

P(X<160)=P(Z<0.5) = 0.691 (69.1%)

thus 69.1% of the woman spend less than $160

7 0
3 years ago
Read 2 more answers
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