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3 years ago

Solving y=6x-11-2x-3y=-7 by substitution

1 answer:

7 0

<span>y=6x-11
-2x-3y=-7
substitute </span>y=6x-11 into -2x-3y=-7

-2x-3y=-7
-2x-3(6x-11)=-7
-2x - 18x + 33 = -7
-20x = -40
x = 2

y = 6x -11
y = 6(2) - 11
y = 1

answer
x = 2 and y =1

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Write a polynomial in standard form that meets the following conditions. Assume a=1 and your function is f(x), The zeros are 5 a

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Polynomials are equations that uses variables and several terms

The polynomial in standard form is f(x) = x^2 - x -20

<h3>How to determine the polynomial</h3>

The polynomial has 2 zeros.

So, the form of the polynomial is:

f(x) = a(x - x1)(x - x2)

The zeros of the polynomial are 5 and -4.

So, the equation becomes

f(x) = a(x - 5)(x + 4)

The value of a = 1.

So, we have;

f(x) = 1(x - 5)(x + 4)

This gives

f(x) = (x - 5)(x + 4)

Expand

f(x) = x^2 - x -20

Hence, the polynomial in standard form is f(x) = x^2 - x -20

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