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3 years ago

(11x + 8) + (8x + 12) =27

Mathematics

2 answers:

Tju [1.3M]3 years ago

7 0

Answer:

11x + 8 +8x +12 =27 (drop the parenthesis, there's no actual need for them)

19x +20 =27 (i combined like terms and then subtracted 20 from both sides)

19x = 7 (divide both sides by 19 to get x alone)

x= 7/19 or 0.36842105 (the answer)

Step-by-step explanation:

prohojiy [21]3 years ago

5 0

Oh wow that person that answered already

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Which angles are corresponding angles?

Arlecino [84]

The correct answer are C. D. and E.

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3 years ago

SOMEONE HELP ME PLEASE! I’m trying to do my homework and this is hard! It’s linear functions. Also it’s number 3

kondaur [170]

Answer:

A. y = 1x + 4

B. 1

C. 4

Step-by-step explanation:

The point (0, 4) is the y-intercept. So b = 4

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y = 1x + 4

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3 years ago

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What does the ordered pair (6,204) represent

Mandarinka [93]

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I can answer the question, but represent in what? Do u got a picture or example or sum?

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3 years ago

This scale balanced when 1111plus+tequals=2424. suppose the left side becomes 1919plus+t.how can you change the right side so th

Charra [1.4K]

8 has been added to 11 to make it 19. 8 must be added to 24 to make it 32.

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3 years ago

A decorative window is made up of a rectangle with semicircles at either end. The ratio of AD to AB is 3:2 and AB is 30 inches.

scZoUnD [109]

Answer: The required ratio will be

$84:1034$

Step-by-step explanation:

Since we have given that

Ratio of AD to AB is 3:2

Length of AB = 30 inches

So, it becomes

$2x=30\\\\x=\frac{30}{2}=15\ inches$

So, Length of AD becomes

$3x=3\times 15=45\ inches$

Now, at either end , there is a semicircle.

Radius of semicircle along AB is given by

$\frac{30}{2}=15\ inches$

So, Area of semicircle along AB and CD is given by

$2\times \frac{\pi r^2}{2}\\\\=\frac{22}{7}\times 15\times 15\\\\=\frac{4950}{7}\ in^2$

Radius of semicircle along AD is given by

$\frac{45}{2}=22.5\ inches$

Area of semicircle along AD and BC is given by

$2\times \frac{1}{2}\pi r^2\\\\=\frac{22}{7}\times \frac{45}{2}\times \frac{45}{2}\\\\=\frac{445500}{28}\ in^2$

And the combined area of the semicircles is given by

$\frac{4950}{7}+\frac{445500}{28}\\\\=\frac{465300}{28}\ in^2$

Area of rectangle is given by

$Length\times width\\\\=AD\times AB\\\\=45\times 30\\\\=1350\ in^2$

Hence, Ratio of the area of the rectangle to the combined area of the semicircles is given by

$1350:\frac{465300}{28}\\\\=1350\times 28:465300\\\\=37800:465300\\\\=84:1034$

Hence, the required ratio will be

$84:1034$

8 0

3 years ago