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finlep [7]
3 years ago
8

If you are changing meters to centimeters, what direction do you move the decimal point?

Mathematics
1 answer:
zysi [14]3 years ago
3 0

to the right. think about it. there's 100 centimeters in a meter so you would want to move the decimal place in a way that increases the value you have.


ex: 5.76 meters. move to the right twice = 576 centimeters

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Hi, please help me out with this math problem.
GalinKa [24]

9514 1404 393

Answer:

  x - 4

Step-by-step explanation:

The expression simplifies to ...

  \sqrt{x^2-8x+16}=\sqrt{(x-4)^2}=|x-4|

For x ≥ 4, the argument of the absolute value function is non-negative, so it remains unchanged. The simplified expression is ...

  x - 4 . . . . for x ≥ 4

6 0
3 years ago
Grant bought 6 packs of stickers for $2 each. How much change will grant receive if he pays with three $5 bills?
Lena [83]

Answer: $3

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3 years ago
Find the circumference of a circle with area of 676 pie square meters<br><br> Please show work
pogonyaev

Step-by-step explanation:

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4 0
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Degger [83]

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the slope is 8/7 and the y-intercept is 300

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Solve for a.
tamaranim1 [39]
The correct answer is:  [C]:  " a =  ± \sqrt{25 - b^2}  " .
<span>___________________________________________________________
Explanation:
_________________________________________________________
We are given:  
_________________________________________________________
    </span>→   "  25  =  a²  +  b²  "  ;   Solve for "a" ; 
_________________________________________________________

    →  To solve for "a" ;  we want to isolate "a" on one side of the equation.
_________________________________________________________
We can rewrite:  "  25  =  a²  +  b²  "  ;

as:  " a²  +  b²  = 25 " .

_________________________________________________________
Then, we can subtract " b² "  from each side of the equation; as follows:
_________________________________________________________

   →
 " a²  +  b²  −  b²  =  25 − b²  "  ;

to get:
_________________________________________________________
   →  " a²  =  25 − b²  "  ;
_________________________________________________________
  →  Now,  take the square root of EACH SIDE of the equation ; 
to isolate "a" on one side of the equation; & to solve for the value(s) of "a" ; 
_________________________________________________________

  →  √(a²)  = \sqrt{25 - b^2}  ;

to get:
_____________________________________________________
  →    a   =  | \sqrt{25 - b^2} |  ;

  →    a   =  ±  \sqrt{25 - b^2}  ; 
  
  →  which is:  Answer choice:  [C]:  " a =  ±  \sqrt{25 - b^2}  " .
______________________________________________________
8 0
3 years ago
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