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Ede4ka [16]
3 years ago
7

Anyone know the answer to this?

Mathematics
1 answer:
Lunna [17]3 years ago
4 0
93 x 2 = 186

x = 186 - 112 
x = 74

y = 2(80) - 74
y = 160 -74
y = 86

360 - 112 - 74 - 86 = 88
z = (88+86)/2
z = 87
You might be interested in
There+are+no+rational+numbers+that+are+also+whole+numbers
meriva
Actually all the whole numbers are kind of rational numbers like : 1/1 , 2/1 , 3/1 , ...
so there are some rational numbers that are whole numbers too :))
i hope this be helpful 
have a nice day 
8 0
3 years ago
Read 2 more answers
Hey shawtys can someone help w this?
NeX [460]

Answer:

its 12 juss round 12

Step-by-step explanation:

8 0
3 years ago
Thelma Thrifty went to her bank. She had a balance of $1,209.76 in her savings account. She withdrew $131.44 and the teller cred
tangare [24]
The answer is B. $1,084.99
When a bank teller credits money into your account it adds money. And when you withdrawal money it takes it out. So you would set up the problem
$1,209.76-$131.44=$1,078.32
Then add the money credited into the account to that total.
$1,078.32+$6.67=$1,084.99
3 0
4 years ago
Bill makes leather shoes. He charges $45 for a pair of women's shoes and $50 for a pair of men's shoes. He sells x pairs of wome
olga_2 [115]
$45x +$50y =$2,500
Since you want to know how many men's shoes he must sell to make $2500 , plug 0 in for x pairs of women's shoes.
$45(0) + $50y =$2,500
0 + $50y =$2,500
$50y = $2,500
$50y/50= $2,500/$50
y = 50

He must sell 50 pairs of men's shoes to still earn his weekly income of $2,500

Check

$45(0) + $50(50) = $2,500
$0 + $2500= $2,500
$2500 = $2500
3 0
4 years ago
If a coin is tossed three times, find probability of getting
Assoli18 [71]

{\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}

‣ A coin is tossed three times.

{\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}

‣ The probability of getting,

1) Exactly 3 tails

2) At most 2 heads

3) At least 2 tails

4) Exactly 2 heads

5) Exactly 3 heads

{\large{\textsf{\textbf{\underline{\underline{Using \: Formula :}}}}}}

\star \: \tt  P(E)= {\underline{\boxed{\sf{\red{  \dfrac{ Favourable \:  outcomes }{Total \:  outcomes}  }}}}}

{\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}

★ When three coins are tossed,

then the sample space = {HHH, HHT, THH, TTH, HTH, HTT, THT, TTT}

[here H denotes head and T denotes tail]

⇒Total number of outcomes \tt [ \: n(s) \: ] = 8

<u>1) Exactly 3 tails </u>

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

\therefore  \sf Probability_{(exactly  \: 3 \:  tails)}  =  \red{ \dfrac{1}{8}}

<u>2) At most 2 heads</u>

[It means there can be two or one or no heads]

Here

• Favourable outcomes = {HHT, THH, HTH, TTH, HTT, THT, TTT} = 7

• Total outcomes = 8

\therefore  \sf Probability_{(at \: most  \: 2 \:  heads)}  =  \green{ \dfrac{7}{8}}

<u>3) At least 2 tails </u>

[It means there can be two or more tails]

Here

• Favourable outcomes = {TTH, TTT, HTT, THT} = 4

• Total outcomes = 8

\longrightarrow   \sf Probability_{(at \: least \: 2 \:  tails)}  =  \dfrac{4}{8}

\therefore  \sf Probability_{(at \: least \: 2 \:  tails)}  =   \orange{\dfrac{1}{2}}

<u>4) Exactly 2 heads </u>

Here

• Favourable outcomes = {HTH, THH, HHT } = 3

• Total outcomes = 8

\therefore  \sf Probability_{(exactly \: 2 \:  heads)}  =  \pink{ \dfrac{3}{8}}

<u>5) Exactly 3 heads</u>

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

\therefore  \sf Probability_{(exactly \: 3 \:  heads)}  =  \purple{ \dfrac{1}{8}}

\rule{280pt}{2pt}

8 0
2 years ago
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