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vova2212 [387]
3 years ago
12

I have attached the question IF ANSWERED WITHIN 10 MINUTES I WILL AWARD BRAINLIEST

Mathematics
1 answer:
Reil [10]3 years ago
8 0
<3 +<4= 180
<3+25+52=180 from here <3=180-77=103
using this in first equation: 103+<4=180  <4=180-103=77
as you can see <4=77 which is the the sum of 25+52
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Can anyone help me with this? I will mark you as brainliest
Nana76 [90]

Answer:

2/7

then 2/14

Step-by-step explanation:

Let P(H)=p be the probability of one head. In many scenarios, this probability is assumed to be p=12 for an unbiased coin. In this instance, P(H)=3P(T) so that p=3(1−p)⟹4p=3 or p=34.

You are interested in the event that out of three coin tosses, at least 2 of them are Heads, or equivalently, at most one of them is tails. So you are interested in finding the likelihood of zero tails, or one tails.

The probability of zero tails would be the case where you only received heads. Since each coin toss is independent, you can multiply these three tosses together: P(H)P(H)P(H)=p3 or in your case, (34)3=2764.

Now we must consider the case where one of your coin flips is a tails. Since you have three flips, you have three independent opportunities for tails. The likelihood of two heads and one tails is 3(p2)(1−p). The reason for the 3 coefficient is the fact that there are three possible events which include two heads and one tails: HHT,HTH,THH. In your case (where the coin is 3 times more likely to have heads): 3(34)2(14)=2764.

Adding those events together you get p3+3(p2)(1−p)=5464. Note that the 3 coefficient

6 0
3 years ago
Read 2 more answers
Write an expression that represents 20.5 (Algebra)
sergij07 [2.7K]
Y=14x+9 the values x=1,2,3
4 0
3 years ago
A person invest 7500 dollars in a bank. The bank pays 6 interest compounded semi-annually. To the nearest tenth of a year,how lo
Kamila [148]

Answer:

Step-by-step explanation:

I clicked see solution

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6 0
3 years ago
12% 0f 72 is what number
earnstyle [38]

12% of 72 is:

=12×72/100

=8.64

So the 12% of 72 is 8.64 is your answer.

7 0
3 years ago
Find a second solution y2(x) of<br> x^2y"-3xy'+5y=0; y1=x^2cos(lnx)
rosijanka [135]

We can try reduction order and look for a solution y_2(x)=y_1(x)v(x). Then

y_2=y_1v\implies{y_2}'=y_1v'+{y_1}'v\implies{y_2}''=y_1v''+2{y_1}'v+{y_1}''v

Substituting these into the ODE gives

x^2(y_1v''+2{y_1}'v+{y_1}''v)-3x(y_1v'+{y_1}'v)+5y_1v=0

x^2y_1v''+(2x^2{y_1}'-3xy_1)v'+(x^2{y_1}''-3x{y_1}'+5y_1)v=0

x^4\cos(\ln x)v''+x^3(\cos(\ln x)-2\sin(\ln x))v'=0

which leaves us with an ODE linear in w(x)=v'(x):

x^4\cos(\ln x)w'+x^3(\cos(\ln x)-2\sin(\ln x))w=0

This ODE is separable; divide both sides by the coefficient of w'(x) and separate the variables to get

w'+\dfrac{\cos(\ln x)-2\sin(\ln x)}{x\cos(\ln x)}w=0

\dfrac{w'}w=\dfrac{2\sin(\ln x)-\cos(\ln x)}{x\cos(\ln x)}

\dfrac{\mathrm dw}w=\dfrac{2\sin(\ln x)-\cos(\ln x)}{x\cos(\ln x)}\,\mathrm dx

Integrate both sides; on the right, substitute u=\ln x so that \mathrm du=\dfrac{\mathrm dx}x.

\ln|w|=\displaystyle\int\frac{2\sin u-\cos u}{\cos u}\,\mathrm du=\int(2\tan u-1)\,\mathrm du

Now solve for w(u),

\ln|w|=-2\ln(\cos u)-u+C

w=e^{-2\ln(\cos u)-u+C}

w=Ce^{-u}\sec^2u

then for w(x),

w=Ce^{-\ln x}\sec^2(-\ln x)

w=C\dfrac{\sec^2(\ln x)}x

Solve for v(x) by integrating both sides.

v=\displaystyle C_1\int\frac{\sec^2(\ln x)}x\,\mathrm dx

Substitute u=\ln x again and solve for v(u):

v=\displaystyle C_1\int\sec^2u\,\mathrm du

v=C_1\tan u+C_2

then for v(x),

v=C_1\tan(\ln x)+C_2

So the second solution would be

y_2=x^2\cos(\ln x)(C_1\tan(\ln x)+C_2)

y_2=C_1x^2\sin(\ln x)+C_2x^2\cos(\ln x)

y_1(x) already accounts for the second term of the solution above, so we end up with

\boxed{y_2=x^2\sin(\ln x)}

as the second independent solution.

6 0
4 years ago
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