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3 years ago

Can someone help me ?

Mathematics

1 answer:

lozanna [386]3 years ago

8 0

Answer:

10 > v (if you don't trust me, check it yourself. Subsitute v for 10 in the first equation.

Step-by-step explanation:

1) 7 > v - 3

2) add 3 to both sides

3) so 7 plus 3 equals 10

So you basically do this

7 > v - 3 (ad 3 to both sides)

You get 10 > v (which is as simplified as possible)

Hope this helps! :)

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Baseball's division series is a best of five game series. That is, the first team to win 3 games is the winner. Team A and team

iris [78.8K]

Answer:

1. 27.46% probability that A wins the series in 3 games.

2. There is a 28.84% probability A wins the series in 4 games.

3. There is a 20.18% probability A wins the series in 5 games.

4. There is a 76.48% probability A wins the series.

5. There is a 71.825% probability A wins the series if a "best-of-three" game series is played.

Step-by-step explanation:

For each game, there are these following probabilities:

A 65% probability team A wins.

A 35% probability team B wins.

The combination formula is important to solve this problem:

This is because for example, team A winning games 1,2 and 4 and team B winning game 3 is the same as team A winning games 1,3,4 and team B winning game 2. That is, the order is not important.

$C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

1. What the probability that A wins the series in 3 games?

This is team A winning all 3 games. For each game, there is a 65% probability that team A wins. So

$P = (0.65)^{3} = 0.2746$

There is a 27.46% probability that A wins the series in 3 games.

2. What is the probability A wins the series in 4 games?

This is the team A winning three games and the team B 1. The team B win cannot happen in the fourth game, so the number of possibilities is a combination of 3 by 2. So

$C_{3,2} = \frac{3!}{2!1!} = 3$

The probability that team A wins the series in 4 games is:

$P = 3*(0.65)^{3}*(0.35) = 0.2884$

There is a 28.84% probability A wins the series in 4 games.

3.What is the probability A wins the series in 5 games?

This is the team A winning three games and the team B 2. The team B second win cannot happen in the fifth game, so the number of possibilities is a combination of 4 by 2. So

$C_{4,2} = \frac{3!}{2!1!} = 6$

The probability that team A wins the series in 5 games is:

$P = 6*(0.65)^{3}*(0.35)^{2} = 0.2018$

There is a 20.18% probability A wins the series in 5 games.

4. What is the probability A wins the series (period)?

They can win the series in 3,4 or 5 games. So this is the sum of the answers for 1,2,3.

$P = 0.2746 + 0.2884 + 0.2018 = 0.7648$

There is a 76.48% probability A wins the series.

5. What is the probability A wins the series if a "best-of-three" game series is played?

These three following outcomes are accepted:

A - A

A - B - A

B - A - A

$P = (0.65)^{2} + 2*(0.65)^{2}*(0.35) = 0.71825$

There is a 71.825% probability A wins the series if a "best-of-three" game series is played.

3 0

3 years ago

Simplify: |-46.09 + 51.64| + |18.08 – 21.52| A. 2.11 B. 3.44 C. 5.55 D. 8.99

guapka [62]

The answer is 2.11.
For negtives i always subtract the numbers: 51.64-46.09
That always helps me

3 0

3 years ago

Read 2 more answers

Rafael is taking a test that contains a section of 12 true-false questions. how many of the possible groups of answers to these

stiv31 [10]

Answer: There are 495 possible different sets of answers the could contain exactly 8 correct answers of false.

Basically, we are looking for the number of different ways of selecting 8 objects out of a set of 12 objects. Our objects are answers of false and the set is the test.

This is a combination problem. The formula would be:

12! / (8! x 4!) = 495

5 0

3 years ago

Hola como estan?Amblo en español y en portugués

Alexxx [7]

Answer:

Olá, how are you going? Amblo

4 0

2 years ago

Read 2 more answers

Part 2!

olga2289 [7]

Math is about number sense and matching patterns. You get number sense by playing with numbers: counting, arranging. Most people do not find it difficult to match patterns, as our brains are wired to see them--sometimes even when they aren't there.

The picture below is pretty much all you need to know to answer these questions. It is a short course on arithmetic and geometric sequences. (We have left out some simplifications that can be made to the formulas for Nth term, and we have not shown formulas for the sum of a sequence.)

1. Geometric sequence with first term 5, common ratio 2. It will have the formula
.. f(n) = 5*2^(n-1) . . . . . . I can't read your picture to tell whether that is B or D

2. Arithmetic sequence with first term 1 and common difference 3. It will have the formula
.. f(n) = 1 +3(n -1) . . . . . . matches A

3. Geometric sequence with first term 2 and common ratio 3/2 = 1.5. It will have the formula
.. f(n) = 2*1.5^(n -1) . . . . . matches C

4. Geometric sequence with first term 600 and common ratio 60/600 = 0.1. It will have the formula
.. f(n) = 600*0.1^(n-1)
This can be simplified using the rules of exponents to
.. f(n) = 600*(0.1^-1)*(0.1^n)
.. f(n) = 6000*0.1^n . . . . . . matches A

5. The sequence is 12, 11, 10, 9, .... It is an arithmetic sequence with first term 12 and common difference -1. It will have the formula
.. f(n) = 12 +(-1)*(n -1)
.. f(n) = 12 -(n -1) . . . . . . matches B

6. This is an arithmetic sequence with first term 8 and common difference -0.5. It will have the formula
.. f(n) = 8 -0.5(n -1)
.. f(n) = 8.5 -0.5n . . . . . . matches C

7 0

3 years ago

Read 2 more answers