Answer
Find out how many eighty fours are in 672.
To prove
Let us assume that the number of the 84 be x .
As given in the equation
Total values given in the question be 672.
Than the equation becomes
84 × x = 672
Simplify the above equation
84x = 672
x = 8
Therefore the Numbers of eighty fours in 672 is 8 .
In y=mx+b, m is the slope and b is the y intercept.
Slope: -2
Y-int: (0,8)
Answer:
x^2 -2xy -10y^2
x^2 -9xy +4 y^2
3x^3 +6x^2 -24 x +27
Step-by-step explanation:
3x^2-5xy -6y^2 -( 2x^2 -3xy+4y^2)
= 3x^2- 2x^2 -5xy +3xy-6y^2 -4 Y^2
= x^2 -2xy -10y^2
2x^2−5xy+y^2 -( x^2+4xy−3y^2)
=2 x^2 -x^2 -5xy -4xy +y^2 +3 y^2
=x^2 -9xy +4 y^2
7x^3−16x+18- (4x^3−6x^2+8x−9)
= 7x^3 -4x^3 + 6x^2-16x- 8x +18 +9
=3x^3 +6x^2 -24 x +27
