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RUDIKE [14]
3 years ago
12

Select the correct answer. Which equation represents a circle?

Mathematics
2 answers:
zloy xaker [14]3 years ago
4 0

Answer:

C

Step-by-step explanation: each side by 4 and you get the radius as 2 and the center at 0,0.

Alex787 [66]3 years ago
3 0

Answer: C

Step-by-step explanation: I got this right on Edmentum.

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Need help with these 2 don’t understand either
Dmitry_Shevchenko [17]
----------------------------------------------------------------
Question 1
----------------------------------------------------------------
a² + b² = c²
9² + 14² = c²
c² = 81 + 196
c² = 277
c= √277
c = 17cm (Rounded to the nearest whole number)

----------------------------------------------------------------
Ans: The Slanted height is 17cm (Answer C)
----------------------------------------------------------------


----------------------------------------------------------------
Question 2
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Lateral area of the cone = πrl
1080π = π(60)l
l =  1080π ÷60π
l = 18.0cm 

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Ans: The slanted height is 18.0cm (Answer D)
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5 0
3 years ago
What is the probability of rolling a 6 and then a 1 on consecutive rolls of a standard, 6-sided number cube?
ratelena [41]

Hello from MrBillDoesMath!

Answer:

1/36



Discussion:

The events of are unrelated ("mutually exclusive") so the probability of both happening is the product of the individual probabilities.  That is,

(1/6) * (1/6) = 1/36


Thank you,

MrB

5 0
3 years ago
Read 2 more answers
Find the common difference of the sequence shown 1/6, 1/4, 1/3
Damm [24]

1/4 - 1/6 = (6-4)/24 = 2/24 = 1/12
1/3 - 1/4 = (4-3)/12 = 1/12



7 0
3 years ago
Read 2 more answers
Please help i am confusion<br> is number 12. -3?
zzz [600]

Answer:

Step-by-step explanation:

5 0
3 years ago
Which term of a AP 5 , 13 , 21 ,... is 181?
Sauron [17]
Here,a(n) =  a + (n-1)d
Here, a = 5, d = 12-5 = 8, a(n) = 181
Substitute this values in to the expression,

181 = 5 + (n-1)8
181-5 = 8n-8
176+8 = 8n
n = 184/8
n = 23

So, it is 23th term of that Arithmetic Progression.

Hope this helps!

7 0
3 years ago
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