Answer:
65m^5n³
Step-by-step explanation:
(13m³n¹)(5m²n²)
GROUP LIKE TERMS
(13×5)(m³+²)(n¹+²) <Remember to use exponential laws
65m^5n³
Answer:
Step-by-step explanation:
![\left[\begin{array}{ccc}7&31\\142&19\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%2631%5C%5C142%2619%5Cend%7Barray%7D%5Cright%5D)
= 7(19) - 142(31) = <em>- 4269</em>
![\left[\begin{array}{ccc}7&11&21\\55&-8&2\\-16&-1&-9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%2611%2621%5C%5C55%26-8%262%5C%5C-16%26-1%26-9%5Cend%7Barray%7D%5Cright%5D)
= 7(- 8)(- 9) + 11(2)(- 16) + 21(55)(- 1) - 21(- 8)(- 16) - 7(2)(- 1) - 11(55)(- 9) = <em>1768</em>
![\left[\begin{array}{ccc}9.07&6.02&2.01\\-30.7&2.5&3.5\\3.55&-1.1&2.35\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D9.07%266.02%262.01%5C%5C-30.7%262.5%263.5%5C%5C3.55%26-1.1%262.35%5Cend%7Barray%7D%5Cright%5D)
= 9.07(2.5)(2.35) + 6.02(3.5)(3.55) + 2.01(- 30.7)(- 1.1) - 2.01(2.5)(3.55) - 9.07(3.5)(- 1.1) - 6.02(- 30.7)(2.35) = <em>647.3561</em>
It’s a black picture. We can’t help with that
Step 1
find the perimeter of a <span>single enclosure
perimeter of a square=4*b
where b is the long side of a square
area square=b</span>²
area square=2025 ft²
b²=2025-------> b=√2025-----> b=45 ft
<span>so
perimeter=4*45-------> 180 ft
step 2
</span>find the perimeter of a two individual enclosure
<span>perimeter=4*20+3*40------> 200 ft
area=20*40*2------> 1600 ft</span>²
<span>
therefore
fencing singular enclosure < fencing two individual enclosure
180 ft < 200 ft
</span>area singular enclosure > area two individual enclosure
2025 ft² > 1600 ft²<span>
the answer is the option
</span><span>a The singular enclosure would minimize cost because it requires 180 feet of fencing.</span><span>
</span>
Answer:
y(y-2)(y+10)
Step-by-step explanation:
when factoring you work with similar concepts and get rid of what you can to make the equation simipler and get your answer like you take a y out of the equation to get y^2 and then reduce and then solve by grouping.
