Hey there!
To solve the first problem, I've found it easiest to solve the equation for, say, values –2 through +2 and create a table of values for you to begin graphing this function. You may need to do more depending on the equation itself.
Some points are: (–2, 0.75), (–1, 1.5), (0, 3), (1, 6) and (2, 12). You can check which graph matches up with these points the closest to get your answer of D.
To solve the second problem, you'll need to use the distance equation.
x1 = –4, y1 = 3
x2 = –1, y2 = 1
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√ (x2–x1)^2 + (y2–y1)^2
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√ (–1–(–4)^2 + (1–3)^2
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√ (–1+4)^2 + (–2)^2
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√ (3)^2 + (–2)^2
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√ 9 + 4
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√ 13, making your answer D
For your third question, I always just counted the number of units the point was from the line of reflection. You'll count twice diagonally towards the line from point C for this one, staying on the "crosshairs" of the graph. All you need to do then is count two diagonal units along the same line, then you'll get your answer of (2, 6), or D.
For your final question, A and B are immediately out, since they won't be parallel to the 4x equation. You'll need to solve both of your remaining equations for y with 2 plugged in for x; whichever one equals 7 will be your answer. In this case, it will be D.
Hope this helped you out! :-)
Answer:
Hydrostatic Force = 35.28KN
Step-by-step explanation:
To solve this question, let's consider integrating the hydrostatic force from the top of the triangle to the bottom.
Formula for a thin horizontal slice of the triangle the force is;
δF=ρgxwδx
Where w is width of triangle; ρ is density of water and g is acceleration due to gravity
At depth x, the width of the triangle is w=2/3x.
Thus, F = (3,0)∫)ρgxwδx
=(2/3)ρg[(3,0)∫)x²δx]
= integrating, we have;
F = (2/3)ρg[(3³/3) - (0³/3)]
F = (2/5)ρg [27/3] = (2/5)(1000)(9.8)(9) = 35280 N = 35.28 KN
Answer:
I think 38.7 if you do<j it would be 38.7
Answer:
Answer is shown in the attachment you can see.
Step-by-step explanation:
