Let volleyball be v and let basketball be b.
v : b = 4 : 7, b = 21
v : 21 = 4 : 7
v/21 = 4/7
7*v = 4*21
v = 4*21/7
v = 4*3
v = 12
Volleyballs are 12
Hope this helps.
4(x -2) +(y +5) = 0 . . . . . an equation
4x +y = 3 . . . . . . . . . . . . the equation in standard form
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A graph can be seen at
https://www.desmos.com/calculator/3ct9gfxclj
Answer:

Step-by-step explanation:
Given that the figure is made up of portion of a square and a semicircle, we have;
BC ≅ AB = 6 cm
The area of semicircle BC with radius BC/2 = 3 is 1/2×π×r² = 1/2×π×3² = 4.5·π cm²
Triangle ABC = 1/2 × Area of square from which ABC is cut
The area of triangle ABC = 1/2×Base ×Height = 1/2×AB×BC = 1/2×6×6 = 18 cm²
The area of the figure = The area of semicircle BC + The area of triangle ABC
The area of the figure = 4.5·π cm² + 18 cm² =
.
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Answer:
Just took the test,
1)d, 3
2)a, -13
3) c, y=-2x+6
4) c, f'(a)=8a+2
Step-by-step explanation:
For #3, graph f(x)=-x^2+5. Next graph y=-2x+6. You will see that the added equation touches at exactly the point (1,4). this make it the tangent line equation