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viktelen [127]
3 years ago
10

Graph the interval[ - 2,0)​

Mathematics
2 answers:
Alina [70]3 years ago
7 0

Answer:

Step-by-step explanation:

i don't know how to draw a line?

-2 solid dot ,then draw a line from -2 to 0 ,at 0 open circle.

ArbitrLikvidat [17]3 years ago
5 0
The point would be on the -2.
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The circumference of a circle is approximately 131.88 centimeters What is the area of the shaded region (6/10 of a circle)
scZoUnD [109]

Answer:

82.97cm^2

Step-by-step explanation:

Given data

Circumference=  131.88 centimeters

We want to find the area of 6/10 part of a circle

Firstly, let us find the area of the circle

We need to get the radius

C= 2πr

131.88= 2*3.142*r

131.88=6.284r

r=  131.88/6.284

r=20.98 cm

Area= πr^2

Area= 3.142*20.98^2

Area= 3.142*440.16

Area= 1382.98cm^2

Hence 6/10 of a 1382.98

=0.06*1382.98

=82.97cm^2

4 0
3 years ago
A candy bar in the shape of a triangular prism has a length of 11 inches. The area of the base of the candy is 1.5 square inches
TEA [102]

Answer:

6.5

Step-by-step explanation:

6 0
3 years ago
How are the GCF and the LCM alike and different?
damaskus [11]
Alike: They both find what's in common.
Difference: LCM finds the least multiple while GCF finds the greatest factor.
4 0
3 years ago
Read 2 more answers
Você é um comandante de uma espaçonave. Sua missão é chegar até Alfa Centauro em cinco anos. A distância do Sol até Alfa Centaur
Deffense [45]

Answer:

The spaceship will get to Alpha Centaur in time

Step-by-step explanation:

<u><em>The complete question in English is</em></u>

You're the commander of a spaceship. Your mission is to reach Alpha Centaur  in five years. The distance from the sun to Alpha Centaur is 2.5 x 10^13 miles. The distance  from Earth to Sun is approximately 9.3 x 10^7

miles. Your spaceship can travel  at the speed of light. You know that light can travel a distance of 5.88 x 10^12  miles in a year. Can you get to Alpha Centaur in time?

step 1

Find the time it takes for the spaceship to travel from Earth to the Sun

The distance from the Earth to Sun is equal to

9.3*10^7\ miles

The spaceship can travel  at the speed of light

The light can travel a distance of 5.88*10^{12}\ miles in a year

so

using a proportion

\frac{5.88*10^{12}\ miles}{1\ year}=\frac{9.3*10^7\ miles}{x}\\\\x=(9.3*10^7)/5.88*10^{12}\\\\x=1.58*10^{-5} \ years

This time is very small in years

Convert to minutes

1.58*10^{-5} \ years=1.58*10^{-5} (365)(24)(60)=8.3\ min

step 2

Find the time it takes for the spaceship to travel from the Sun to Alpha Centaur

The distance from the the Sun to Alpha Centaur is equal to

2.5*10^{13}\ miles

The spaceship can travel  at the speed of light

The light can travel a distance of 5.88*10^{12}\ miles in a year

so

using a proportion

\frac{5.88*10^{12}\ miles}{1\ year}=\frac{2.5*10^{13}\ miles}{x}\\\\x=(2.5*10^{13})/5.88*10^{12}\\\\x=4.25\ years

4.25\ years< 5\ years

therefore

The spaceship will get to Alpha Centaur in time

3 0
3 years ago
Combine like terms to create an equivalent expression -4/7p+(-2/7p)+1/7
STatiana [176]
-6/7p+1/7 um Idk what you wanted me to do but I added -4/7p with -2/7p
7 0
3 years ago
Read 2 more answers
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