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Flauer [41]
3 years ago
14

YALL PLEASE HELP FRFR

Mathematics
2 answers:
VLD [36.1K]3 years ago
7 0

Answer:

JUST TOOK THE ASSIGNMENT

1. Virginia

2. Maryland

3. Washington D.C.

so you dont have to read all of that above!!

Step-by-step explanation:


Arturiano [62]3 years ago
3 0

First of all, let's note the sales tax rates in each town. In Washington, we know it's 6%. In the town in Virginia, it's 5%. In the town in Maryland, it's 9%.

Let's figure out the total taxes in every town by applying the sales tax rate for each town.

To add percents to a whole number, we always multiply using 0.XX (example: to add 1% to a the number 100, we would multiply 100*0.01 and get the answer 1. We'd then add the 1 to the original number, 100, and get 101.)


In this case, we need to multiply the $1000 by the sales tax in Washington, 6%.

1000 x 0.06 = 60. Now, we add the 60 to the original number (1000), and get 1060. Now we know the total tax in Washington on the computer will be $60, and the total price we will pay is $1060.00


For Virginia, the sales tax is 5%. Let's add the 5% using the same method we used in the equation above.

1000 x 0.05 = 50. Now, add the 50 to the original 1000, and we get 1050. Now we know that the total tax in Virginia is going to be $50, and the total price that we'll pay in Virginia is $1050.00.


On to the final town, Maryland. In Maryland, the sales tax rate is 9%. Let's use the same formula again.

1000 * 0.09 = 90. Now that we have the 90, we add it to the original 1000, and we get 1090. In Maryland the total sales tax will be $90, and the total price we'll pay is $1090.00.


Now, let's complete the question by answering the 3 parts.


To spend the least amount total Amir should buy the computer in Virginia ($1050.00).

Amir would pay the most sales tax in Maryland ($90.00).

Amir would pay $60 sales tax in Washington, DC.


I hope this answer was in depth enough to help you out so that you can do this on your own in the future. :)

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Step-by-step explanation:

Solution for What is 75 percent of 600:

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Now we have: 75 percent of 600 = 450

Question: What is 75 percent of 600?

Percentage solution with steps:

Step 1: Our output value is 600.

Step 2: We represent the unknown value with $x$x​.

Step 3: From step 1 above,$600=100\%$600=100%​.

Step 4: Similarly, $x=75\%$x=75%​.

Step 5: This results in a pair of simple equations:

$600=100\%(1)$600=100%(1)​.

$x=75\%(2)$x=75%(2)​.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

600

x​=

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Step 7: Again, the reciprocal of both sides gives

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Mkey [24]

Answer:

X = \begin{bmatrix}1&3\\ 2&4\end{bmatrix}

Step-by-step explanation:

The question we have at hand is, in other words,

\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}\left(X\right)=\begin{bmatrix}8&20\\ \:3&7\end{bmatrix} - where we have to solve for the value of X

If we have to isolate X here, then we would have to take the inverse of the following matrix ...

\begin{bmatrix}4&2\\ \:1&1\end{bmatrix} ... so that it should be as follows ... \begin{bmatrix}4&2\\ \:1&1\end{bmatrix}^{-1}

Therefore, we can conclude that the equation as to solve for " X " will be the following,

X=\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1}\begin{bmatrix}8&20\\ 3&7\end{bmatrix} - First find the 2 x 2 matrix inverse of the first portion,

\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1} = \frac{1}{\det \begin{pmatrix}4&2\\ 1&1\end{pmatrix}}\begin{pmatrix}1&-2\\ -1&4\end{pmatrix}= \frac{1}{2}\begin{bmatrix}1&-2\\ -1&4\end{bmatrix} = \begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}

At this point we have to multiply the rows of the first matrix by the rows of the second matrix,

X = \begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}\begin{bmatrix}8&20\\ 3&7\end{bmatrix} ,

X = \begin{pmatrix}\frac{1}{2}\cdot \:8+\left(-1\right)\cdot \:3&\frac{1}{2}\cdot \:20+\left(-1\right)\cdot \:7\\ \left(-\frac{1}{2}\right)\cdot \:8+2\cdot \:3&\left(-\frac{1}{2}\right)\cdot \:20+2\cdot \:7\end{pmatrix} - Simplifying this, we should get ...

\begin{bmatrix}1&3\\ 2&4\end{bmatrix} ... which is our solution.

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