We know that
the equation of the parabola is of the form
y=ax²+bx+c
in this problem
y=1/4x²−x+3
where
a=1/4
b=-1
c=3
the coordinates of the focus are
(-b/2a,(1-D)/4a)
where D is the discriminant b²-4ac
D=(-1)²-4*(1/4)*3-----> D=1-3---> D=-2
therefore
x coordinate of the focus
-b/2a----> 1/[2*(-1/4)]----> 2
y coordinate of the focus
(1-D)/4a------> (1+2)/(4/4)---> 3
the coordinates of the focus are (2,3)
Answer: -5(p-4)
Step-by-step explanation: The coefficient of a variable is the number multiplying it. To factor it, take the coefficient out and put it outside the parantheses. However, if you do that, make sure you take that coefficient out of all of your other terms!
Answer:y=
1
2
x4+
7
2
x3+
9
2
x2+
−27
2
x−27
Step-by-step explanation:
