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3 years ago

What is the x intercept?

Mathematics

1 answer:

Harlamova29_29 [7]3 years ago

7 0

The line that is horizontal on a graph
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Joanne signed up for 24 dancing lessons she took 3/4 of the by April and 1/5 of them by May .What part of dancing lesson did she

gavmur [86]

Answer:

$Part = \frac{19}{20}$

$Lessons = 23$

Step-by-step explanation:

Given:

$Dancing\ Lessons = 24$

$April = \frac{3}{4}$

$May = \frac{1}{5}$

Required:

Determine the part she took

To solve this, we simply add up the part she took in April and May.

$Part = \frac{3}{4} + \frac{1}{5}$

Take LCM

$Part = \frac{15 + 4}{20}$

$Part = \frac{19}{20}$

Hence, she took $\frac{19}{20}$ of the dancing lesson.

However, to calculate the number of lesson.

We have to multiply $\frac{19}{20}$ by the total dancing lessons.

$Lessons = \frac{19}{20} * 24$

$Lessons = \frac{19* 24}{20}$

$Lessons = \frac{456}{20}$

$Lessons = 22.8$

$Lessons = 23$ ---- Approximated

6 0

3 years ago

Find the sum of X + y, when x= 3.1, and y= 5.4

Mashutka [201]

So all this is is changing the x and y variables,

In this case, x = 3.1 and y = 5.4 so,

3.1 + 5.4

3 + 5 = 8

.1 + .4 = .5

8.5

4 0

3 years ago

Which number has the greatest absolute value?

AysviL [449]

Answer:

Step-by-step explanation:

3 0

2 years ago

Molly buys a scooter for $26.99. Robert buys a basketball for $12.89. How much more does Molly spend more money than Robert?

erastovalidia [21]

Molly spends 14.10 more on her scooter. I did this by doing 26.99 - 12.89.

7 0

3 years ago

Given f(x)=e^-x^3 find the vertical and horizontal asymptotes

Aleonysh [2.5K]

Given:

$f\mleft(x\mright)=e^{-x^3}$

To find the vertical and horizontal asymptotes:

The line x=L is a vertical asymptote of the function f(x) if the limit of the function at this point is infinite.

But, here there is no such point.

Thus, the function f(x) doesn't have a vertical asymptote.

The line y=L is a vertical asymptote of the function f(x) if the limit of the function (either left or right side) at this point is finite.

$\begin{gathered} y=\lim _{x\rightarrow\infty}e^{-x^3} \\ =e^{-\infty} \\ y=0 \\ y=\lim _{x\rightarrow-\infty}e^{-x^3} \\ y=e^{\infty} \\ =\infty \end{gathered}$

Thus, y = 0 is the horizontal asymptote for the given function.

5 0

1 year ago