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PilotLPTM [1.2K]
3 years ago
15

A store sells 8 small, 18 medium, and 20 large sweatshirts. Each sweatshirt costs $16. How much money, m, is the store paid for

all the sweatshirts they sell?
Mathematics
1 answer:
Novosadov [1.4K]3 years ago
4 0

Answer:

8+18+20x16 ,

Step-by-step explanation: yeah .

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The soccer teams in a club league are ordering new jerseys. The cost is $18 per jersey plus $10 shipping per team.
Lelechka [254]

Answer:

10*7+ 18x *7 =2590

or 70 + 18x*7  =2590

Step-by-step explanation:

10*7 to find out how much the shipping costs for the 7 teams altogether

18*x  because you need to find how much the jerseys cost for all the soccer teams

then multiply it by 7 to find how many players on each team

when you solve for x you get 20

there are 20 players on each on team.

4 0
3 years ago
the cost of four scarves and six hats is $52.00.the cost of two hats is $1 more then the cost of 1 scarf.how much does 1 scarf c
Elden [556K]
Please elaborate more on your question so I can help you
7 0
3 years ago
What is 2 to the power of 2?
padilas [110]
Okay, so you are talking about exponents, so what you are talking about is 2², to find the answer to the exponent you multiply the same number as many times as the exponent (little number) says, so in here we are going to multiply 2 x 2 and the answer is 4. So 2 to the power of 2 is 4.
5 0
3 years ago
F(x) 3x^4-4x^2-3<br> Is this function odd?
Karo-lina-s [1.5K]

Answer:

No.

Step-by-step explanation:

f(x) = 3x^4-4x^2-3

If a function is odd then  f(-x) = -f(x) for all values of x.

Here f(-x) = 3(-x)^4 - 4(-x)^2 - 3

= 3x^4 - 4x^2 - 3

So f(-x) = f(x) which makes it even.

8 0
3 years ago
The Henley's took out a loan for $195,000 to purchase a home. At a 4.3% interest rate
ella [17]

Interest paid after 30 years is $494,546.99.

Solution:

Principal (P) = $195,000

Interest rate (r) = 4.3%

Time (t) = 30 years

n = number of times interest calculated per year

n = 1

Compound interest formula:

$A=P\left(1+\frac{r}{n}\right)^{n t}

where A is the final amount

$A=195000\left(1+\frac{4.3\%}{1}\right)^{1\times 30}

$A=195000\left(1+\frac{4.3}{100}\right)^{30}

$A=195000\left(\frac{100+4.3}{100}\right)^{30}

$A=195000\left(\frac{104.3}{100}\right)^{30}

A = 689546.99

Interest = Amount  - Principal

             = 689546.99 - 195000

             = 494546.99

Interest paid after 30 years is $494,546.99.

6 0
4 years ago
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