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nata0808 [166]
2 years ago
6

Use the quadratic formula to solve the equation.

Mathematics
1 answer:
allochka39001 [22]2 years ago
7 0
=1.3+0.1sqrt29, 1.3-0.1sqrt29
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54 + 81 = 9(6 +_) I need the help to answer my question
Otrada [13]

Answer:

9

Step-by-step explanation:

54+81=9(6+9)

9 times 9 equals 81

7 0
3 years ago
Read 2 more answers
True or false is the graph of y = 2/3 x + 4
Licemer1 [7]

Answer:

False. 2/3 is positive so therefore, it would be increasing, not decreasing.

Step-by-step explanation:

6 0
3 years ago
Donald spent half as much as Patricia did on presents this year, and Carl spent 3 times more than Donald. If the total spent bet
Nuetrik [128]

Answer:

Patricia spent $24 on presents, while Donald spent $12 and Carl spent $36.

Step-by-step explanation:

The problem is to solve how much money each person spent on presents in the year, through a series of equivalences. In order to determine how much money each one spent, the following equation must be proposed:

Patricia = X

Donald = 1 / 2X

Carl = 3/2 X

X + 1 / 2X + 3 / 2X = 72

1X + 0.5 X + 1.5 X = 72

3X = 72

X = 72/3

X = 24

Thus, Patricia spent $ 24 on presents, while Donald spent $ 12 (2/24) and Carl spent $ 36 (1.5 x 24).

4 0
2 years ago
Solve : 13(3+2x)−1=10
Vinvika [58]
X= -14/13

Solve for X by simplifying both sides of the equation, the isolating the variable.

I hope this helps.
4 0
3 years ago
1 − 2 + 3 −... + 99 <br> Please solve!
Lemur [1.5K]

Answer:

50

Step-by-step explanation:

So you can think of this by grouping it like this:

(1-2) + (3-4) + (5-6) + ... + (97-98) + 99

which is equal to: (-1) + (-1) + (-1)... + (-1) + 99

(each group is equal to -1, and 99 won't have a pair since it's the last one)

then, find how many groups of -1 there are:

the groups start at 1 and end at 98, but there are two in each group, so 98/2 = 49. this means there are 49 groups.

so now, you know that there are 49 -1s, so 49 * (-1) = -49.

finally, you can't forget the extra 99 that didn't have a pair, so -49 + 99 = 50.

6 0
1 year ago
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