Answer:
D)$42.00
Step-by-step explanation:
18 3/4 is equal to 18.75, so 18.75x2.80 is your original cost (52.5). After doing that, since 52.5=100% you are going to divide 52.5 by 5 since 20x5=100. So 20% is 10.5. 52.5-10.5= $42.00
Answer:
-10
Step-by-step explanation:
9^-8 x 9^-2 = a^b
We know that x^y * x^z = x^(y+z)
9^-8 x 9^-2 = 9^(-8+-2) = 9^(-10)
a= 9
b = -10
Answer: Option B, Option C, Option E
Step-by-step explanation:
The options written correctly, are:

For this exercise you need to use the following Inverse Trigonometric Functions:

When you have a Right triangle (a triangle that has an angle that measures 90 degrees) and you know that lenght of two sides, you can use the Inverse Trigonometric Functions to find the measure of an angle
:

Therefore, the conclusion is that the angles "x" and "y" can be found with these equations:

Well, to write the definition of "Perpendicular lines form right angel" using "if and only if". the sentence would become :
<em>
</em><em>Two lines are perpendicular if and only if they form a right angle
</em><em>
</em><em />Hope this helps