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eimsori [14]
3 years ago
5

From the set {(-2, -5), (0, 10), (5, 8), (8, -3)}, which ordered pairs are a part of the solution set for 5x + 5y > 45?

Mathematics
1 answer:
Anton [14]3 years ago
3 0
Let's go through each of the given points and plug in the coordinates

-----------------------------------------------
Plug in (x,y) = (-2,-5)

5x + 5y > 45
5(-2) + 5(-5) > 45 ... replace x with -2; replace y with -5
-10 - 25 > 45
-35 > 45

The last inequality is false, so (-2,-5) is not in the solution set.

-----------------------------------------------
Plug in (x,y) = (0, 10)

5x + 5y > 45
5*0 + 5*10 > 45
0 + 50 > 45
50 > 45

The last inequality is true so (0,10) is in the solution set
-----------------------------------------------
Plug in (x,y) = (5,8)

5x + 5y > 45
5*5 + 5*8 > 45
25+40 > 45
65 > 45

The last inequality is true so (5,8) is in the solution set
-----------------------------------------------
Plug in (x,y) = (8,-3)

5x + 5y > 45
5*8 + 5*(-3) > 45
40 - 15 > 45
25 > 45

The last inequality is false, so (8,-3) is not in the solution set
-----------------------------------------------
Summary: The points (0, 10) and (5,8) are in the solution set

Check out the attached image to see a visual representation of this. 
Notice how point B and point C are in the red shaded region. 

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Find the measure of the missing angle <br><br> Answer: a=
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About 33% of people who get their feet examined are found to have an ingrown toenail. What is the probability of a podiatrist ex
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The correct answer is 0.94147

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Let A denote the event that the podiatrist finds the first person with an ingrown toenail.

And (1 - A) denote the event that the podiatrist does not find the ingrown toenail.

While examining seven people, the podiatrist can find the very first person to have an ingrown toenail. Similarly he can find the second patient to have the ingrown toenail. Going in this way the probability of the first person to have an ingrown toenail is given by:

= A + (1 - A) × A + (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × (1 - A) × (1 - A) × A + (1 - A) × (1 - A) ×  (1 - A) × (1 - A) × (1 - A) × (1 - A) × A.

= \frac{1}{3} + \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} .

= \frac{1}{3} + \frac{2}{3} \frac{1}{3} + (\frac{2}{3}) ^{2} \frac{1}{3} + (\frac{2}{3})^{3} \frac{1}{3} + (\frac{2}{3})^{4} \frac{1}{3} + (\frac{2}{3})^{5} \frac{1}{3} + (\frac{2}{3})^{6} \frac{1}{3}.

= 0.94147

We can also solve the above expression by using the geometric progression formula as well where common ratio is given by \dfrac{2}{3}.

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3 years ago
CAn you pls help me on this one ?
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